我是正则表达式的新手,我发现很难完成这个简单的任务。整个字符串看起来像
debug1: Authentications that can continue: publickey,gssapi-with-mic,password
debug1: Next authentication method: publickey
debug1: read PEM private key done: type RSA
debug1: Enabling compression at level 6.
debug1: Authentication succeeded (publickey).
debug1: channel 0: new [client-session]
debug1: Entering interactive session.
debug1: Sending subsystem: sftp
Can't ls: "/home/dev/customer/*.out" not found
debug1: client_input_channel_req: channel 0 rtype exit-status reply 0
debug1: channel 0: free: client-session, nchannels 1
debug1: fd 0 clearing O_NONBLOCK
debug1: fd 2 clearing O_NONBLOCK
debug1: Transferred: stdin 0, stdout 0, stderr 0 bytes in 0.1 seconds
debug1: Bytes per second: stdin 0.0, stdout 0.0, stderr 0.0
debug1: Exit status 0
debug1: compress outgoing: raw data 343, compressed 184, factor 0.54
debug1: compress incoming: raw data 860, compressed 430, factor 0.50
我只需要检查此字符串中是否存在*.out/text" not found
之类的内容。它确实存在于这种情况下,但我没有得到输出为真
我使用的正则表达式.*\*\..*" not found.*
不起作用。有人可以帮忙吗?
答案 0 :(得分:0)
你真的不需要正则表达式。一个简单的字符串匹配将工作得很好,也更快!例如:
$ fgrep '.out" not found' /tmp/foo
Can't ls: "/home/dev/customer/*.out" not found
如果你坚持使用,你可以使用正则表达式,但是对于你的用例它不会更好。不过,这里是:
$ egrep '\.out" not found' /tmp/foo
Can't ls: "/home/dev/customer/*.out" not found
正则表达式的技巧是确保只匹配最小必要文本以确保正确匹配,而不是尝试使用正则表达式标记构造整行。在这种情况下,简单就更好了。
答案 1 :(得分:0)
import java.util.regex.*;
class Main
{
public static void main (String[] args) throws java.lang.Exception
{
java.io.BufferedReader in = new java.io.BufferedReader (new java.io.InputStreamReader (System.in));
String input = "";
String s;
while ((s = in.readLine()) != null && s.length() != 0) input += s;
Pattern pattern = Pattern.compile("\\*\\.(?:out|text)\\\"\\s+not\\sfound");
Matcher matcher = pattern.matcher(input);
if (matcher.find())
System.out.println("Match found");
}
}
测试此代码here。
答案 2 :(得分:-1)
这适用于多行和单行模式
(^.*?|.*?)\.(out|text).*?not found(.*?|.*?$)