Doctrine2命名查询

时间:2012-08-18 06:21:58

标签: symfony doctrine-orm

我在Doctrine2中找不到任何有关命名查询的文档。 请帮忙。 Doctrine2是否具有命名查询功能?

4 个答案:

答案 0 :(得分:23)

您可以使用

  1. NamedQuery - DQL。实施例

    use Doctrine\ORM\Mapping\NamedQuery;
    use Doctrine\ORM\Mapping\NamedQueries;
    
    /**
    * @Entity
    * @Table(name="cms_users")
    * @NamedQueries({
    *     @NamedQuery(name="activated", query="SELECT u FROM __CLASS__ u WHERE u.status = 1")
    * })
    */
    class CmsUser
    {}
    

    并称之为

    $this->getDoctrine()->getRepository('MyBundle:CmsUser')
        ->createNamedQuery('activated')
        ->getResult();
    
  2. NamedNativeQuery - SQL。更多信息请访问:http://docs.doctrine-project.org/en/latest/reference/native-sql.html#named-native-query

  3. 在EntityRepository中收集查询,例如:

    namespace Acme\StoreBundle\Repository;
    
    use Doctrine\ORM\EntityRepository;
    
    class ProductRepository extends EntityRepository
    {
        public function findAllOrderedByName()
        {
            return $this->getEntityManager()
                ->createQuery('SELECT p FROM AcmeStoreBundle:Product p ORDER BY p.name ASC')
                ->getResult();
        }
    }
    

    此处提供更多信息:http://symfony.com/doc/current/book/doctrine.html#custom-repository-classes

  4. 此处类似的主题: https://groups.google.com/forum/?fromgroups#!topic/doctrine-user/K-D5ta5tZ3Y[1-25]

答案 1 :(得分:2)

也许您会对EntityRepositories感兴趣,您可以在其中创建和存储复杂的Doctrine查询,并在项目中调用您想要的主题:

http://symfony.com/doc/current/book/doctrine.html#custom-repository-classes

答案 2 :(得分:0)

如果您不想搞乱实体定义,可以在存储库的构造函数中调用注释表示法内部使用的函数:

namespace MyBundle\Repository;

use Doctrine\ORM\EntityRepository;

class CmsUserRepository extends EntityRepository
{
    public function __construct($em, \Doctrine\ORM\Mapping\ClassMetadata $class)
    {
        $this->getClassMetadata()->addNamedQuery(array(
            'name'  => 'activated',
            'query' => 'SELECT u FROM __CLASS__ u WHERE u.status = 1'
        ));
    }
}

您还可以使用实体的命名空间和类替换语句的__CLASS__部分,例如MyBundle\Entity\CmsUser

答案 3 :(得分:0)

我发现这个问题正在寻找Native Named Query示例,上面的答案帮助了我,所以我想我会以同样的方式分享如何进行原生命名查询。

将其添加到实体存储库的构造函数

public function __construct($em, \Doctrine\ORM\Mapping\ClassMetadata $class)
{
    parent::__construct($em, $class);
    $this->getClassMetadata()->addNamedNativeQuery(
        array('name' => 'published', 
              'query' => 'SELECT 
                  t0.id AS id, 
                  t0.tracking_uri AS tracking_uri, 
                  t0.name AS name, 
                  t0.description AS description, 
                  t0.url_name AS url_name,
                  t0.status_type_id as status_type_id
                FROM 
                  store.store t0 
                WHERE 
                  t0.status_type_id = 2', 
               'resultClass' => '__CLASS__',
               'resultSetMapping' => array('entities' => array('entityClass' => '__CLASS__',
                                                               'fields'      => array('id'           => 'id',
                                                                                      'tracking_url' => 'tracking_url',
                                                                                      'name'         => 'name',
                                                                                      'description'  => 'description',
                                                                                      'url_name'     => 'url_name',
                                                                                      'status_type'  => 'status_type_id')))));
}

这是我对此

的测试的剪辑
public function testNamedNativeQueryPublished()
{
    $results = $this->em->getRepository('MyBundle:Store')->createNativeNamedQuery('published')->execute();

    foreach ($results as $store)
    {
        $this->assertEquals(2, $store->getStatusType());
    }
}