为什么PHPMyAdmin上的结果与SQL小提琴不同？

时间：2012-08-17 17:58:03

标签： mysql phpmyadmin sqlfiddle

我尝试在phpmyadmin和sql小提琴中输入查询。 我认为时区与此有关。其中一个转换时考虑了时区而另一个没有考虑。 结果也不同。对于小提琴，结果是这样的。

    ORDR    DAY                COUNT    AGGREGATE   AVERAGE PREVIOUS PERIOD VOTE VELOCITY   (COALESCE(T_1.COUNT, 0) - COALESCE(T_2.COUNT, 0)) * 100.0/ COALESCE (T_2.COUNT, 0)
      16    August, 11 2012     1              1    0                                                    (null)
      17    August, 12 2012     1              2    0.0625                                              (null)
      18    August, 13 2012     4              9    0.2941                                              0
      19    August, 14 2012     1              13   0.6667                                              600

这是针对phpmyadmin 

 ORDR   DAY                COUNT    AGGREGATE   AVERAGE PREVIOUS PERIOD VOTE VELOCITY   (COALESCE(T_1.COUNT, 0) - COALESCE(T_2.COUNT, 0)) * 100.0/ COALESCE (T_2.COUNT, 0)              
  14    2012-08-11             1    1             0.0000                                     50.00000
  15    2012-08-12             1    2              0.0714                                    -66.66667
  1     2012-08-13             6    8              NULL                                 NULL 
  2     2012-08-14             3    11             8.0000                              NULL

这是小提琴的链接。  http://sqlfiddle.com/#!2/ef77b/106 这是phpmyadmin的查询。

drop table if exists sampleData;
create table sampleData
(
     id int NOT NULL AUTO_INCREMENT,
      timecode int, 
     count int,
      PRIMARY KEY (id)
    )
-- #ENGINE=MyISAM
;
INSERT INTO sampleData
(timecode, count)
VALUES
(1344893440, 1), ( 1346014720, 1),( 1344898688,1),( 1345654784,1),( 1345978368,1),
( 1345959296,1), (1345064704,1), ( 1345156352,1),( 1345225600,1),
(1345017984,1),( 1345640960,1),( 1346019968,1),( 1345834752,1),
( 1345438464,1),( 1344986880,1),( 1345045632,1),( 1345557888,1),( 1344973056,1),( 1345087232,1),( 1345433216,1),( 1345691008,1),
( 1344917760,1),( 1345253248,1),( 1344934912,1),( 1345890048,1),( 1345272448,1), (1345829504,1),( 1345798400,1),( 1345203200,1),( 1344741120,1),
( 1345175552,1),( 1344824192,1),( 1344926336,1),( 1345571712,1),( 1344931584,1),( 1345211776,1),( 1345059456,1),( 1345516288,1),( 1345441920,1),( 1346009472,1);


set @t3.id=0;
set @t3.id2=0;  -- must differentiate the ids because if not, they will increase and will not match. That is, there will not be 3 identical columns but 1 very long column. 
set @t3.id3=0;
select t.*,
       (coalesce(t_1.count, 0) - coalesce(t_2.count, 0)) * 100.0/ coalesce (t_2.count, 0) 
from 
    (SELECT @t3.id:=@t3.id+1 AS ordr,
     t3.day, t3.count , SUM(t2.count) AS AGGREGATE  , (SUM(t2.count)-t3.count)/(@t3.id) AS "average previous period vote velocity"
    -- (count(t3.count)-1) as "number of people voted",
    FROM
    (
    SELECT   t1.id, t1.hour, t1.day, sum(t1.count ) AS COUNT
    FROM
    (
      (SELECT id, hour(time(FROM_UNIXTIME( timecode)))  AS hour,
       date(FROM_UNIXTIME( timecode))  AS DAY,
      (FROM_UNIXTIME( timecode)) AS original, COUNT(1)  AS 'count'
       FROM sampleData
      WHERE hour(time(FROM_UNIXTIME( timecode)))>=14
       GROUP BY DAY)
     UNION ALL
      (SELECT id, hour(time(FROM_UNIXTIME( timecode))) AS hour,
       date(FROM_UNIXTIME( timecode-86400) ) AS DAY,
       (FROM_UNIXTIME( timecode)) AS original, COUNT(1)  AS 'count'
      FROM sampleData
      WHERE hour(time(FROM_UNIXTIME( timecode)))< 14
       GROUP BY DAY)
    )  t1
    GROUP BY t1.DAY -- no need count
    HAVING COUNT(*)>0
    ORDER BY t1.DAY
    ) t3
    INNER JOIN
    (
      (SELECT hour(time(FROM_UNIXTIME( timecode)))  AS hour,
       date(FROM_UNIXTIME( timecode))  AS DAY,
      (FROM_UNIXTIME( timecode)) AS original, COUNT(1)  AS 'count'
       FROM sampleData
      WHERE hour(time(FROM_UNIXTIME( timecode)))>=14
       GROUP BY DAY)
     UNION ALL
      (SELECT hour(time(FROM_UNIXTIME( timecode))) AS hour,
       date(FROM_UNIXTIME( timecode-86400) ) AS DAY,
       (FROM_UNIXTIME( timecode)) AS original, COUNT(1)  AS 'count'
      FROM sampleData
      WHERE hour(time(FROM_UNIXTIME( timecode)))< 14
       GROUP BY DAY)
    )  t2
    ON t3.DAY>=t2.DAY
    GROUP BY t3.DAY, t3.COUNT
    ORDER BY t3.DAY)t 
left outer join
    (SELECT @t3.id2:=@t3.id2+1 AS ordr,
     t3.day, t3.count , SUM(t2.count) AS AGGREGATE  , (SUM(t2.count)-t3.count)/(@t3.id2) AS "average previous period vote velocity"
    -- (count(t3.count)-1) as "number of people voted",
    FROM
    (
    SELECT   t1.id as id2, t1.hour, t1.day, sum(t1.count ) AS COUNT
    FROM
    (
      (SELECT id, hour(time(FROM_UNIXTIME( timecode)))  AS hour,
       date(FROM_UNIXTIME( timecode))  AS DAY,
      (FROM_UNIXTIME( timecode)) AS original, COUNT(1)  AS 'count'
       FROM sampleData
      WHERE hour(time(FROM_UNIXTIME( timecode)))>=14
       GROUP BY DAY)
     UNION ALL
      (SELECT id, hour(time(FROM_UNIXTIME( timecode))) AS hour,
       date(FROM_UNIXTIME( timecode-86400) ) AS DAY,
       (FROM_UNIXTIME( timecode)) AS original, COUNT(1)  AS 'count'
      FROM sampleData
      WHERE hour(time(FROM_UNIXTIME( timecode)))< 14
       GROUP BY DAY)
    )  t1
    GROUP BY t1.DAY -- no need count
    HAVING COUNT(*)>0
    ORDER BY t1.DAY
    ) t3
    INNER JOIN
    (
      (SELECT hour(time(FROM_UNIXTIME( timecode)))  AS hour,
       date(FROM_UNIXTIME( timecode))  AS DAY,
      (FROM_UNIXTIME( timecode)) AS original, COUNT(1)  AS 'count'
       FROM sampleData
      WHERE hour(time(FROM_UNIXTIME( timecode)))>=14
       GROUP BY DAY)
     UNION ALL
      (SELECT hour(time(FROM_UNIXTIME( timecode))) AS hour,
       date(FROM_UNIXTIME( timecode-86400) ) AS DAY,
       (FROM_UNIXTIME( timecode)) AS original, COUNT(1)  AS 'count'
      FROM sampleData
      WHERE hour(time(FROM_UNIXTIME( timecode)))< 14
       GROUP BY DAY)
    )  t2
    ON t3.DAY>=t2.DAY
    GROUP BY t3.DAY, t3.COUNT
    ORDER BY t3.DAY) t_1
     on t.ordr = t_1.ordr + 1 
left outer join
    (SELECT @t3.id3:=@t3.id3+1 AS ordr,
     t3.day, t3.count , SUM(t2.count) AS AGGREGATE  , (SUM(t2.count)-t3.count)/(@t3.id3) AS "average previous period vote velocity"
    -- (count(t3.count)-1) as "number of people voted",
    FROM
    (
    SELECT   t1.id as id3, t1.hour, t1.day, sum(t1.count ) AS COUNT
    FROM
    (
      (SELECT id, hour(time(FROM_UNIXTIME( timecode)))  AS hour,
       date(FROM_UNIXTIME( timecode))  AS DAY,
      (FROM_UNIXTIME( timecode)) AS original, COUNT(1)  AS 'count'
       FROM sampleData
      WHERE hour(time(FROM_UNIXTIME( timecode)))>=14
       GROUP BY DAY)
     UNION ALL
      (SELECT id, hour(time(FROM_UNIXTIME( timecode))) AS hour,
       date(FROM_UNIXTIME( timecode-86400) ) AS DAY,
       (FROM_UNIXTIME( timecode)) AS original, COUNT(1)  AS 'count'
      FROM sampleData
      WHERE hour(time(FROM_UNIXTIME( timecode)))< 14
       GROUP BY DAY)
    )  t1
    GROUP BY t1.DAY -- no need count
    HAVING COUNT(*)>0
    ORDER BY t1.DAY
    ) t3
    INNER JOIN
    (
      (SELECT hour(time(FROM_UNIXTIME( timecode)))  AS hour,
       date(FROM_UNIXTIME( timecode))  AS DAY,
      (FROM_UNIXTIME( timecode)) AS original, COUNT(1)  AS 'count'
       FROM sampleData
      WHERE hour(time(FROM_UNIXTIME( timecode)))>=14
       GROUP BY DAY)
     UNION ALL
      (SELECT hour(time(FROM_UNIXTIME( timecode))) AS hour,
       date(FROM_UNIXTIME( timecode-86400) ) AS DAY,
       (FROM_UNIXTIME( timecode)) AS original, COUNT(1)  AS 'count'
      FROM sampleData
      WHERE hour(time(FROM_UNIXTIME( timecode)))< 14
       GROUP BY DAY)
    )  t2
    ON t3.DAY>=t2.DAY
    GROUP BY t3.DAY, t3.COUNT
    ORDER BY t3.DAY) t_2
     on t.ordr = t_2.ordr + 2

0 个答案:

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