我在Scala Playframework中有一个数据库表定义为
CREATE TABLE account (
id SERIAL,
email TEXT NOT NULL,
buffer BYTEA NOT NULL,
PRIMARY KEY (id)
);
我正在使用协议缓冲区将对象序列化为具有以下代码的字节数组
DB.withConnection{ implicit c=>
SQL("INSERT INTO device (buffer,secret) VALUES ({secret},{buffer})").on(
"secret"->device.getSecret(),
"buffer"->device.toByteArray()
).executeInsert()
}
device.toByteArray()
返回的类型为Array[Byte]
,其中应该匹配该列的数据库类型。但是在执行代码时我得到了
play.core.ActionInvoker$$anonfun$receive$1$$anon$1: Execution exception [[PSQLException: ERROR: column "buffer" is of type bytea but expression is of type character varying
Hint: You will need to rewrite or cast the expression.
Position: 44]]
at play.core.ActionInvoker$$anonfun$receive$1.apply(Invoker.scala:134) [play_2.9.1.jar:2.0.3]
at play.core.ActionInvoker$$anonfun$receive$1.apply(Invoker.scala:115) [play_2.9.1.jar:2.0.3]
at akka.actor.Actor$class.apply(Actor.scala:318) [akka-actor.jar:2.0.2]
at play.core.ActionInvoker.apply(Invoker.scala:113) [play_2.9.1.jar:2.0.3]
at akka.actor.ActorCell.invoke(ActorCell.scala:626) [akka-actor.jar:2.0.2]
at akka.dispatch.Mailbox.processMailbox(Mailbox.scala:197) [akka-actor.jar:2.0.2]
Caused by: org.postgresql.util.PSQLException: ERROR: column "buffer" is of type bytea but expression is of type character varying
答案 0 :(得分:4)
查看anorm source和Postgres docs,您似乎需要使用Array[Byte]
而不是{{1}添加正确存储setBytes
的处理程序当前代码所要求的。
我会在框架中的anyParameter中扩展匹配以读取
setObject
并添加
value match {
case Some(bd: java.math.BigDecimal) => stmt.setBigDecimal(index, bd)
case Some(b: Array[Byte]) => stmt.setBytes(index, b)
case Some(o) => stmt.setObject(index, o)
// ...
你应该可以在框架之外通过这里的类型类魔术来做到这一点,但我现在没有时间弄明白。