我的一位朋友要求我恢复1994年用剪辑器编写的程序的密码。我给自己一个反编译器(Valkyrie 5)并反编译了EXE文件。我找到了一个名为USERLOGIN的程序。问题是我不知道如何在限幅器中编程。如果有人可以编辑程序以便不再要求身份验证,我将非常感谢。
#include "common.ch"
#include "inkey.ch"
********************************
Function USERLOGON
Local Local1:= -1, Local2:= .F., Local3, Local4, Local5:= 3, ;
Local6:= 3, Local7:= 7, Local8:= 41, Local9, Local10, Local11, ;
Local12, Local13, Local14, Local15
Local3:= 1
Local9:= {}
Local13:= setcursor()
If (!netuse(diskname() + ":" + dirname() + "\" + "sinusr.dbf", ;
"users"))
Return Local1
EndIf
dbSetFilter({ || users->valid })
Local14:= box(Local5, Local6, Local7, Local8, Nil, ;
coltonum("GR+/B"))
Do While (!Local2)
Local10:= Space(12)
Local11:= Space(10)
setcursor(1)
If (!Empty(n_shellver()))
Local10:= padr(nnetwhoami(), 12)
EndIf
wininfo(Local14, @Local5, @Local6, @Local7, @Local8)
@ Local5 + 1, Local6 + 5 Say "User............." Color "GR+/B"
SetPos(Row(), Col() + 1)
AAdd(Local9, __Get({ |_1| IIf(ISNIL(_1), Local10, Local10:= ;
_1) }, "cUName", "@K!", Nil, Nil):display())
@ Local5 + 2, Local6 + 5 Say "Password........." Color "GR+/B"
SetPos(Row(), Col() + 1)
AAdd(Local9, __Get({ |_1| IIf(ISNIL(_1), Local11, Local11:= ;
_1) }, "cUPass", "@K!", Nil, Nil):display())
Local9[2]:reader({ |_1| gt_grpassw(_1) })
wreadmodal(Local9, 0)
Local11:= Local9[2]:cargo()
Local9:= {}
If (LastKey() == K_ESC .OR. !winisinuse(Local14))
If (winisinuse(Local14))
winclose(Local14)
EndIf
Return Local1
EndIf
Local10:= alltrim(Local10)
Local12:= {}
Locate For Local10 == alltrim(users->emri)
Do While (Found())
AAdd(Local12, users->id)
Continue
EndDo
For Local4:= 1 To Len(Local12)
If ((Local15:= upass(Local12[Local4])) != Nil)
If (alltrim(Local11) == Local15)
Local2:= .T.
Exit
EndIf
EndIf
Next
EndDo
If (users->id != Local12[Local4])
users->(dbGoTop())
Locate For Local12[Local4] == users->id
If (!Found())
msg("Fatal error in user's file !", 3)
Return -1
EndIf
EndIf
For Local4:= 1 To MaxCol()
winchgpos(0, 3)
Next
boxc(Local14)
setcursor(Local13)
If (users->in)
tone(500, 10)
Local4:= al_box("User " + Trim(users->emri) + ;
" is already IN;" + "Do You Want to Jump In ?", 2, ;
{" Yes ", " No "}, 2, "WARNING")
If (Local4 == 1)
msg("More than One User with the same Name might cause Trouble !", ;
3)
Else
Close
Return -1
EndIf
ElseIf (netrlock())
Replace users->in With .T.
Unlock
dbcommit()
Else
Close
Return -1
EndIf
Static148[1]:= users->id
Static148[2]:= alltrim(users->emri)
Static148[3]:= alltrim(users->dirpriv)
Static148[4]:= users->gjuha1
Static148[5]:= users->gjuha2
Static148[6]:= alltrim(users->emriiplote)
Local1:= Static148[1]
Close
Return Local1
* EOF
答案 0 :(得分:0)
这是部分猜测,但这是我的解释:
从控制台将用户密码读入Local9[2]
:
@ Local5 + 2, Local6 + 5 Say "Password........." Color "GR+/B"
...
Local9[2]:reader({ |_1| gt_grpassw(_1) })
wreadmodal(Local9, 0)
将密码放入Local11
:
Local11:= Local9[2]:cargo()
通过Local12
Local10
Locate For Local10 == alltrim(users->emri)
Do While (Found())
AAdd(Local12, users->id)
Continue
EndDo
将每个用户的密码设为Local15
,如果密码的当前和与Local11
中的密码匹配,请验证用户:
For Local4:= 1 To Len(Local12)
If ((Local15:= upass(Local12[Local4])) != Nil)
If (alltrim(Local11) == Local15)
Local2:= .T.
Exit
EndIf
EndIf
Next
修复
只需删除密码检查代码即可。不确定所有其余代码的目的,我建议不要管它。我保留了用户密码的检索,因为有可能没有登录没有密码的用户(也许这就是帐户被禁用的方式。上面的最后一个块可以改为:
For Local4:= 1 To Len(Local12)
If ((Local15:= upass(Local12[Local4])) != Nil)
Local2:= .T.
EndIf
Next