Question

这可能是一个简单而愚蠢的问题，但首先我正在学习php，所以你的帮助将不胜感激。

我正在尝试使用指定的条件语句获取变量。

$gender = $curauth->gender; // getting from wordpress user profile.

if($gender === 'Male') {
    echo 'his';
} else {
    echo 'her';
}

所以我想要做的是它会检查用户是否是男性，而不是在某些描述中它将使用他的，如果是女性，它将使用她。像下面的东西

echo 'jatin soni doesn't have set this option yet. His option will be deactivated soon.';

所以这里他的将使用上面的条件代码设置。

Answer 1

你可以直接echo：

echo 'jatin soni doesn\'t have set this option yet. ', 
     ($gender === 'Male' ? 'His' : 'Her'), 
     ' option will be deactivated soon.';

如果您需要多次或出于可读性原因，则应将其分配给变量：

# Default Female:
$gender = empty($curauth->gender) ? 'Female' : $curauth->gender;

$hisHer = $gender === 'Male' ? 'His' : 'Her';
echo 'jatin soni doesn\'t have set this option yet. ', 
     $hisHer, 
     ' option will be deactivated soon.';

下一步可以是double-quoted strings^Docs中的变量替换或使用printf^Docs函数进行格式化输出。

Answer 2

这个怎么样？

<?php
$pronoun = $curauth->gender == 'Male' ? 'his' : 'her';
echo "Jatin Soni doesn't have set this option yet. " .
     ucfirst($pronoun) . " option will be deactivated.\n"
?>

Answer 3

最常见的做法是将动态部分分配给变量，然后在输出中使用变量：

$gender = $curauth->gender; // getting from wordpress user profile.

if ($gender === 'Male') {
    $hisHer = 'His';
} else {
    $hisHer = 'Her';
}

echo "jatin soni doesn't have set this option yet. $hisHer option will be deactivated soon.";

Answer 4

如果您想要变量，可以在一行中完成：

$gender = $curauth->gender; // getting from wordpress user profile.
$their = $gender == 'Male' ? $gender = 'His' : $gender = 'Her';
echo "$username doesn't have set this option yet. $their option will be deactivated soon.";

PHP：如果Else条件赋值给变量并调用string

4 个答案: