Question

我有一个存储函数，它应该计算我的工资单的周开始日期。哪个是“星期四”但是我的存储过程总是让我的开始日期为“星期五”我的声明和设置功能有什么问题？我希望我的StartWeekDay为“星期四”...帐户表中“lStartday”设置为“5”我的代码如下：

DECLARE @StartWeekDay int 
SET @StartWeekDay = (Select lStartDay From Account Where lLocationID = 1)

DECLARE @CurrentDate DateTime 
SET @CurrentDate = GetDate()
DECLARE @CurrentWeekDay int
SET @CurrentWeekDay = DATEPART(dw,@CurrentDate)

DECLARE @Diff int
SET @Diff = @StartWeekDay - @CurrentWeekDay

SET @Diff = Case When @Diff > 0 Then -6 When @Diff = 0 Then 0 Else @Diff End

--
 DECLARE @DaysToStart int
 SET @DaysToStart = (DatePart(dw,@CurrentDate) - @StartWeekDay)
 IF @DaysToStart <= .1 
  BEGIN
    SET @DaysToStart = @DaysToStart + 7 
  END

 DECLARE @myStartWeekDate DateTime
 --SET @myStartWeekDate = dbo.DateOnly(DATEADD(d,@Diff,@CurrentDate))
 SET @myStartWeekDate =  Convert(nvarchar,DateAdd(d,-@DaysToStart,@CurrentDate),101) -- getting DATE only
--

Answer 1

以下查询是将日期舍入到本周开始的标准方法。然而，这被视为星期一......

DATEADD(WEEK, DATEDIFF(WEEK, 0, @YourDate), 0)

如果您将值偏移3，则会将函数更改为向上舍入到上一个星期四...

DATEADD(WEEK, DATEDIFF(WEEK, 0, @YourDate-3), 3)

编辑：这应该是3，而不是4 ......

SET @yourDate    = getDate()
SET @firstDay    = 3
SET @RoundedDate = DATEADD(WEEK, DATEDIFF(WEEK, 0, @YourDate-@firstDay), @firstDay)

 Value of @firstDay | Day of week this will round to
--------------------+--------------------------------
        0           |        Monday
        1           |        Tuesday
        2           |        Wednesday
        3           |        Thursday
        4           |        Friday
        5           |        Saturday
        6           |        Sunday

Answer 2

lStartDay = 5将永远给你星期五。你需要为星期四添加4

DECLARE @DaysToStart int
 SET @DaysToStart = (DatePart(dw,@CurrentDate) - @StartWeekDay)
 IF @DaysToStart <= .1 
  BEGIN
    SET @DaysToStart = @DaysToStart + 7 
  END

如果你声明@DaysToStart并且DatePart也返回INT，为什么要与.1进行比较

Answer 3

        DECLARE @StartWeekDay int 
    SET @StartWeekDay = 5

    DECLARE @CurrentDate DateTime 
    SET @CurrentDate = '8/24/2012'
    DECLARE @CurrentWeekDay int
    SET @CurrentWeekDay = DATEPART(dw,@CurrentDate)
    SELECT @CurrentWeekDay;

    DECLARE @Diff int
    SET @Diff = @StartWeekDay - @CurrentWeekDay

    SET @Diff = Case When @Diff > 0 Then -6 When @Diff = 0 Then 0 Else @Diff End

    --
     DECLARE @DaysToStart int
     SET @DaysToStart = (DatePart(dw,@CurrentDate) - @StartWeekDay)
--change here to <1 and not <=1 that will add 8 and return friday at the end
     IF @DaysToStart < 1 
      BEGIN
        SET @DaysToStart = @DaysToStart + 7 
      END
      SELECT @DaysToStart;
     DECLARE @myStartWeekDate DateTime
     --SET @myStartWeekDate = dbo.DateOnly(DATEADD(d,@Diff,@CurrentDate))
     SET @myStartWeekDate =  Convert(nvarchar,DateAdd(d,-@DaysToStart,@CurrentDate),101) 
     SELECT @myStartWeekDate

如何计算每周开始日期

3 个答案: