Question

我有一个数组，我试图删除访问空格，括号和“来自nsarray以便使用componentsSeparatedByString:@";"

NSArray *paths = [dic valueForKey:@"PATH"];

    for(NSString *s in paths)
    {
        NSLog(@"String: %@", s);
    }

String: (
"29858,39812;29856,39812;29800,39819;29668,39843;29650,39847;29613,39855;29613,39855;29613,39856;29605,39857;29603,39867;29603,39867;29599,39892;29596,39909;29587,39957;29571,40018;29563,40038;29560,40043"
)

这是输出给出显示有空格，括号和“我怎么能删除它们？由于此行是juz，该数组"29858,39812;29856,39812;29800,39819;29668,39843;29650,39847;29613,39855;29613,‌39855;29613,39856;29605,39857;29603,39867;29603,39867;29599,39892;29596,39909;295‌87,39957;29571,40018;29563,40038;29560,40043" this line is a string inside the path array内的一个字符串，我尝试使用componentsSeparatedByString:@";"，所有空格括号和“内部”都无法溢出。

Answer 1

尝试stringByTrimmingCharactersInSet：

NSCharacterSet *charsToTrim = [NSCharacterSet characterSetWithCharactersInString:@"()  \n\""];
s = [s stringByTrimmingCharactersInSet:charsToTrim];

Answer 2

尝试使用：

s = [s stringByReplacingOccurrencesOfString:@";"
                                     withString:@""];

Answer 3

它为您分隔数字，您可以使用它们作为NSInteger值。

NSString *_inputString = @"29858,39812;29856,39812;29800,39819;29668,39843;29650,39847;29613,39855;29613,39855;29613,39856;29605,39857;29603,39867;29603,39867;29599,39892;29596,39909;29587,39957;29571,40018;29563,40038;29560,40043";
NSString *_setCommonSeparator = [_inputString stringByReplacingOccurrencesOfString:@";" withString:@","];
NSArray *_separetedNumbers = [_setCommonSeparator componentsSeparatedByString:@","];

for (NSString *_currentNumber in _separetedNumbers) {
    NSInteger _integer = [_currentNumber integerValue];
    NSLog(@"number : %d", _integer);
}

如何删除空格，括号和“从nsarray

3 个答案: