Question

我正在开发一个应用程序，我需要在其中显示联系人应用程序中的联系人。

我已成功实现了该功能，但现在我只需要显示在本机联系人应用程序中选择的类似Magic Jack（http://itunes.apple.com/us/app/free-calls-with-magicjack/id463926997?mt=8）iPhone应用程序的组中的联系人。

我试图搜索谷歌，论坛，苹果的文档，但无法找到解决方案。任何人都可以帮助我吗？

我使用下面的代码来获取所有联系信息。

ABAddressBookRef addressBook = ABAddressBookCreate(); 
ABRecordRef source = ABAddressBookCopyDefaultSource(addressBook); 
NSArray *persons = (NSArray *)(ABAddressBookCopyArrayOfAllPeopleInSourceWithSortOrdering(addressBook, source, kABPersonSortByFirstName));

Answer 1

以下是您可以使用的代码，它会获取姓名。

-(IBAction)handlingClick:(id)sender
{
    ABPeoplePickerNavigationController *peopleController = [[ABPeoplePickerNavigationController alloc] init];
    peopleController.peoplePickerDelegate = self;
    [self presentModalViewController:peopleController animated:YES];
    [peopleController release];

}

-(void)peoplePickerNavigationControllerDidCancel:(ABPeoplePickerNavigationController *)peoplePicker
{
    [peoplePicker  dismissModalViewControllerAnimated:YES];
}

-(BOOL)peoplePickerNavigationController:(ABPeoplePickerNavigationController *)peoplePicker
     shouldContinueAfterSelectingPerson:(ABRecordRef)person 
                               property:(ABPropertyID)property 
                             identifier:(ABMultiValueIdentifier)identifier
{
    return NO;
}

-(BOOL)peoplePickerNavigationController:(ABPeoplePickerNavigationController *)peoplePicker
     shouldContinueAfterSelectingPerson:(ABRecordRef)person
{
    self.firstName.text = (NSString*)ABRecordCopyValue(person, kABPersonFirstNameProperty);
    self.lastName.text = (NSString*)ABRecordCopyValue(person, kABPersonLastNameProperty);

    [self dismissModalViewControllerAnimated:YES];
    return NO;

}

Answer 2

ABGroupCopyArrayOfAllMembers不适合你想要的吗？

从本机联系人应用程序中检索选定的组

2 个答案: