我很抱歉，如果我不清楚这一天，我想要做的是逐行采取文本文件，并根据行开始将确定将其发送到哪个表。我遇到的问题是找到最好（最有效）的方式来发送某些以单词或“[”开头的行。这是我正在加载的文本文件的示例，它是日志，并且Exception，Message和Source可以在文本文件的任何位置。以“[”开头的行转到（LogTable），以“Exception”开头的行将转到（ExceptionTable），但每个“Exception”都连接到前一个Log行，所以我也在寻找一种方法连接这两个，以便它们可以在数据库中链接。我试图遍历文件中的每一行，并确定使用linq查询需要使用哪个表并将更改保存到mySQL数据库。
[2012-07-05 00:01:07,008] [INFO ] [MessageManager] [3780] () [] [Starting ProcessNewMessageEvent]
[2012-07-05 00:01:07,008] [INFO ] [MessageManager] [3780] () [] [Method: RegValue]
[2012-07-05 00:01:07,008] [DEBUG] [MessageManager] [3780] () [] [reg: InstallPath]
Exception: System.ServiceModel.EndpointNotFoundException
Message: There was no endpoint listening at that could accept the message. This is often caused by an incorrect address or SOAP action. See InnerException, if present, for more details.
Source: mscorlib
[2012-07-04 23:55:59,598] [INFO ] [MessageManager] [6616] () [] [Method: RegValue]
[2012-07-04 23:55:59,598] [DEBUG] [MessageManager] [6616] () [] [reg: InstallPath]
这段代码没有循环它会执行第一个循环然后它会在最后一节中被“grougquery”查询捕获并且不会遍历整个“for”循环，所以当它到达“异常：”时它抛出一个例外。有没有比我在这里做的更有效的方法呢？我找不到一种不同的方式？再次感谢
foreach (string s in filePaths)
{
string[] lines = System.IO.File.ReadAllLines(s);
for (int i = 0; i < lines.Length; i++)
{
if (lines[i].Contains("Exception:"))
{
var exQuery = from exMessage in lines
let logRecord = exMessage.Split(':')
select new ExTable()
{
ExlogException = logRecord[i],
ExlogMessage = logRecord[i + 1],
ExlogSource = logRecord[i + 2],
};
foreach (var item in exQuery)
{
exception ex = new exception();
ex.LogException = item.ExlogException;
ex.LogMessage = item.ExlogMessage;
ex.LogSource = item.ExlogSource;
ex.LogServerStackTrace = item.ExlogServerStackTrace;
ex.LogExRethrown = item.ExlogRethrown;
}
}
else if (lines[i].Contains("["))
{
var groupQuery = from date in lines
let logRecord = date.Split('[', ']', '(', ')')
select new OLog()
{
OlogDate = logRecord[1],
OlogLevel = logRecord[3],
OlogLogger = logRecord[5],
OlogThread = logRecord[7],
OlogProperty = logRecord[9],
OlogMethod = logRecord[11],
OlogException = logRecord[12],
};
foreach (var item in groupQuery)
{
temp temp = new temp();
temp.logDate = item.OlogDate;
temp.logLevel = item.OlogLevel;
temp.logLogger = item.OlogLogger;
temp.logThread = item.OlogThread;
temp.logProperty = item.OlogProperty;
temp.logMethod = item.OlogMethod;
temp.logException = item.OlogException;
logEntity.temps.AddObject(temp);
}
}
}
logEntity.SaveChanges();
}
答案 0 :(得分：0)
使用SSIS进行集成，它将更容易，它可以帮助您拆分文本文件 http://social.technet.microsoft.com/wiki/contents/articles/3172.aspx
答案 1 :(得分：0)
你按行划分，然后按'：'，它看起来像你的异常跨越3行，因此你的行数组中有3个不同的值，所以你的第二个拆分不会按预期工作。
实现我认为你想要完成的工作的一种方法是迭代线数组，然后在遇到它们时处理这些情况，如下所示：
foreach (string s in filePaths) {
//goes through each line in each file
string[] lines = System.IO.File.ReadAllLines(s);
for (int i=0;i < lines.Length; i++)
{
if (line[i].Contains("Exception:"))
{
// Handle line[i] as Exception, line[i+1] as Message, line[i+2] as Source
}
else if (line[i].Contains("["))
{
// Same as you had before
}
}
// same as before
}
答案 2 :(得分：0)
以下是我认为你要做的事情...以一种比一种for循环更有条理的方式。
注意，这个例子是在LinqPad（linqpad.com）中运行的，我推荐使用linq代码。它给出了预期的结果。
void Main()
{
string [] lines = {
"[2012-07-05 00:01:07,008] [INFO ] [MessageManager] [3780] () [] [Starting ProcessNewMessageEvent]",
"[2012-07-05 00:01:07,008] [INFO ] [MessageManager] [3780] () [] [Method: RegValue]",
"[2012-07-05 00:01:07,008] [DEBUG] [MessageManager] [3780] () [] [reg: InstallPath]",
@"Exception: System.ServiceModel.EndpointNotFoundException
Message: There was no endpoint listening at that could accept the message. This is often caused by an incorrect address or SOAP action. See InnerException, if present, for more details.
Source: mscorlib",
"[2012-07-04 23:55:59,598] [INFO ] [MessageManager] [6616] () [] [Method: RegValue]",
"[2012-07-04 23:55:59,598] [DEBUG] [MessageManager] [6616] () [] [reg: InstallPath]"
};
var exceptions = lines.Where(l => l.Contains("Exception:"))
.Select(line =>
{
var items = line.Split(':');
var result = new
{
OlogException = items.ElementAtOrDefault(1),
OlogMessage = items.ElementAtOrDefault(2),
OlogSource = items.ElementAtOrDefault(3),
OlogServerStackTrace = items.ElementAtOrDefault(4)
};
return result;
});
var groups = lines.Where(l => l.StartsWith("["))
.Select(line =>
{
var items = line.Split('[', ']', '(', ')');
var result = new
{
OlogDate = items.ElementAtOrDefault(1),
OlogLevel = items.ElementAtOrDefault(3),
OlogLogger = items.ElementAtOrDefault(5),
OlogThread = items.ElementAtOrDefault(7),
OlogProperty = items.ElementAtOrDefault(9),
OlogMethod = items.ElementAtOrDefault(11),
OlogException = items.ElementAtOrDefault(13)
};
return result;
});
exceptions.Dump();
groups.Dump();
}