Question

我有2个uibutton和1个标签，长压力限制在这些控制之下。当在任何控件上进行longpress时，如何获取下面发生longpress的对象是我写的代码。

UIButton *btn = [UIButton buttonWithType:UIButtonTypeRoundedRect];
btn.frame = CGRectMake(80.0, 210.0, 160.0, 40.0);
[btn addTarget:self action:@selector(wasDragged:withEvent:) forControlEvents:UIControlEventTouchDragInside];
//[self.view addSubview:btn];
btn.userInteractionEnabled = YES;

// add it
[self.view addSubview:btn];
UILongPressGestureRecognizer *longPress = [[UILongPressGestureRecognizer alloc]
                                           initWithTarget:self 
                                           action:@selector(handleLongPress:)];
longPress.minimumPressDuration = 1.0;
[btn addGestureRecognizer:longPress];

下面是在longpress上调用的函数

-(void)handleLongPress:(id)sender{
 }

如果我打印发件人的描述，那么我得到

 <UILongPressGestureRecognizer: 0x6aa4480; state = Began; view = <UIRoundedRectButton 0x6aa9570>; target= <(action=handleLongPress:, target=<ViewController 0x6a8cc60>)>>

从中我怎样才能在长时间事件发生时获得对象的参考我的意思是我怎么知道我是否自称UiLabel或Uibutton？

Answer 1

只需检查UIGestureRecognizer（父类）视图属性：

@property（非原子，只读）UIView * view

手势识别器附加到的视图。（只读）

@property（非原子，只读）UIView *视图   讨论   使用addGestureRecognizer：方法将手势识别器附加（或添加）到UIView对象。

Answer 2

-(void)handleLongPress:(UILongPressGestureRecognizer *)sender{


    if ([sender.view isKindOfClass:[UIButton class]]) {

            UIButton *myButton = (UIButton *)sender.view; // here is your sender object or Tapped button

            if (myButton.tag == 1) {

                    //sender is first Button. Because we assigned 1 as Button1 Tag when created.
            }
            else if (myButton.tag == 2){

                    //sender is second Button. Because we assigned 2 as Button2 Tag when created.
            }
    }

    if ([sender.view isKindOfClass:[UILabel class]]) {

        UILabel *myLabel = (UILabel *)sender.view; // here is your sender object or Tapped label.

    }


}

与uibutton和uilabel的UILongPressGestureRecognizer问题

2 个答案: