交叉编译PHP

时间:2012-08-15 14:47:03

标签: php linux embedded cross-compiling

我已下载PHP 5.4.0源代码,将其解压缩并移至源文件夹中。

我使用以下命令配置:

./configure --build=x86_64-unknown-linux-gnu --host=arm-linux-uclibcgnueabi --prefix=/usr/arm/www CC="arm-linux-uclibcgnueabi-gcc --sysroot=/toolchains/gnu_cortex-a9_tools/"  --disable-libxml --disable-dom  --without-iconv --without-openssl --disable-simplexml --disable-xml --disable-xmlreader --disable-xmlwriter --without-pear --without-sqlite3 --disable-pdo --without-pdo-sqlite --disable-phar  --with-config-file-path=/etc/

其次是

make

没有错误,一切都运行良好。 接下来我做一个make install。

make install

一切都运行良好。 我将它移动到目标平台并运行

/usr/arm/www/bin/php -v
PHP 5.4.0 (cli) (built: Aug 15 2012 16:07:41) 
Copyright (c) 1997-2012 The PHP Group
Zend Engine v2.4.0, Copyright (c) 1998-2012 Zend Technologies

我用我的网络服务器和php直接测试一个简单的主页。

<?php echo "hello" ?>
# php index.php
hello

它按预期工作。 接下来我测试:

<?php
$output = shell_exec('ls -lart');
echo "<pre>$output</pre>";
?>

哦,不!〜

# php shell.php 

Segmentation fault

我设定了另一个剧本:

#!/bin/php
<?php

echo "hello";
$handle = fopen("info.txt", "r");
echo $handle;
?>

结果相同:

# php index.php 
helloSegmentation fault

我有php.ini吗?

# /usr/arm/www/bin/php --ini
Configuration File (php.ini) Path: /etc/
Loaded Configuration File:         /etc/php.ini

是的,没有禁用的功能。 测试strace / usr / arm / www / bin / php index.php

lstat("/srv/www/info.txt", {st_mode=S_IFREG|0644, st_size=20, ...}) = 0
open("/srv/www/info.txt", O_RDONLY)     = 3
fstat(3, {st_mode=S_IFREG|0644, st_size=20, ...}) = 0
lseek(3, 10, SEEK_CUR)                  = 0
--- SIGSEGV (Segmentation fault) @ 0 (0) ---
+++ killed by SIGSEGV +++

文件info.txt存在,并且它已经预先读取/写入它。

测试strace / usr / arm / www / bin / php shell.php

fcntl64(3, F_GETFL)                     = 0 (flags O_RDONLY)
ioctl(3, SNDCTL_TMR_TIMEBASE or TCGETS, 0x7e31fddc) = -1 EINVAL (Invalid argument)
vfork()                                 = 3324
close(4)                                = 0
fstat(3, {st_mode=S_IFIFO|0600, st_size=0, ...}) = 0
read(3, "total 24\n-rw-rw-r--    1 1001    "..., 8192) = 468
read(3, ""..., 8192)                    = 0
--- SIGCHLD (Child exited) @ 0 (0) ---
close(3)                                = 0
wait4(3324, [{WIFEXITED(s) && WEXITSTATUS(s) == 0}], 0, NULL) = 3324
--- SIGSEGV (Segmentation fault) @ 0 (0) ---
+++ killed by SIGSEGV +++

如果我通过gdb运行index.php,它会给我:

Starting program: /usr/arm/www/bin/php index.php
hello
Program received signal SIGSEGV, Segmentation fault.
zend_do_fcall_common_helper_SPEC (execute_data=0x2ac7a040) at /home/maiden/Downloads/php-5.4.0/Zend/zend.h:391
391 /home/maiden/Downloads/php-5.4.0/Zend/zend.h: No such file or directory.
    in /home/maiden/Downloads/php-5.4.0/Zend/zend.h

gdb从shell.php给我这个 启动程序:/ usr / arm / www / bin / php shell.php

Program received signal SIGSEGV, Segmentation fault.

zend_do_fcall_common_helper_SPEC (execute_data=0x2ab76040) at /home/maiden/Downloads/php-5.4.0/Zend/zend.h:391
391 in /home/maiden/Downloads/php-5.4.0/Zend/zend.h

zend.h位于/ usr / arm / www / include / php / Zend / 显然在交叉编译过程中出了问题。我错过了什么?我没有找到任何配置标志来纠正这一点,并创建一个符号链接到所需的位置删除gdb输出,但PHP仍然是段错误。

感谢您的帮助!

更新

# valgrind php test.php
==2181== Memcheck, a memory error detector
==2181== Copyright (C) 2002-2012, and GNU GPL'd, by Julian Seward et al.
==2181== Using Valgrind-3.8.0 and LibVEX; rerun with -h for copyright info
==2181== Command: php test.php
==2181==
==2181== Conditional jump or move depends on uninitialised value(s)
==2181==    at 0x4004EC8: ??? (in /lib/ld-uClibc-0.9.30-nptl.so)
==2181==
==2181== Invalid read of size 4
==2181==    at 0x4004D48: _dl_get_ready_to_run (in /lib/ld-uClibc-0.9.30-nptl.so)
==2181==  Address 0x7d4cc304 is just below the stack ptr.  To suppress, use: --workaround-gcc296-bugs=yes
==2181==
==2181== Invalid read of size 4
==2181==    at 0x48C348C: __uClibc_main (in /lib/libuClibc-0.9.30-nptl.so)
==2181==  Address 0x7d4cc554 is just below the stack ptr.  To suppress, use: --workaround-gcc296-bugs=yes
==2181==
==2181== Invalid write of size 4
==2181==    at 0x233010: __eqdf2 (ieee754-df.S:1120)
==2181==  Address 0x7d4cb0bc is just below the stack ptr.  To suppress, use: --workaround-gcc296-bugs=yes
==2181==
Warning: shell_exec(): Unable to execute 'ls -lart' in /test.php on line 3
==2181== Invalid read of size 4
==2181==    at 0x1FF1AC: zend_do_fcall_common_helper_SPEC (zend.h:391)
==2181==    by 0x1F3D17: execute (zend_vm_execute.h:410)
==2181==    by 0x18B217: zend_execute_scripts (zend.c:1279)
==2181==    by 0x1365BB: php_execute_script (main.c:2473)
==2181==    by 0x22B52B: do_cli (php_cli.c:988)
==2181==    by 0x22BD4B: main (php_cli.c:1364)
==2181==  Address 0x8 is not stack'd, malloc'd or (recently) free'd
==2181==
Segmentation fault

UPDATE2

使用memcheck重新运行valgrind,获得与之前相同的输出,但这是新的:

php: can't resolve symbol '__libc_freeres'

UPDATE3

虽然valgrind让我失望,但我继续使用gdb,我在目标系统上创建了文件夹/home/maiden/..etc并复制了我的php / include文件夹的内容并重新运行gdb。现在我收到此错误消息:

(gdb) run index.php 
Starting program: /bin/php index.php
hello
Program received signal SIGSEGV, Segmentation fault.
zend_do_fcall_common_helper_SPEC (execute_data=0x2ab34040) at /home/maiden/Downloads/php-5.4.5/Zend/zend.h:391
warning: Source file is more recent than executable.
391     return --pz->refcount__gc;

这与sixeightzero在昨天的评论中所写的非常相似。 我现在尝试了PHP版本5.3.5,5.4.0,5.4.5相同的错误。

此主题已被关闭! :( 续下:https://serverfault.com/questions/418521/cross-compile-php [已关闭] 现在开始:Cross compile PHP with UCLIBC

0 个答案:

没有答案