我编写了一个程序,要求用户使用字符串输入一个数字,然后程序会将该数字转换为十进制,但是当我编译(使用-lm)并运行a时我遇到了问题.out,我得到一个Segmentation故障(核心转储),不确定在哪里看或如何解决它,还有一个问题我需要什么,以便它打印转换的结果(printf(“东西......”) ))?
#include <stdio.h>
#include <string.h>
#include <math.h>
int main()
{
char string[100];
int s;
char a;
char j;
int sum;
printf("B = B to D\n");
printf("D = D to B\n");
printf("choose which one to convert to:");
scanf("%c%c", &a, &j);
if (a == 'B')
{
printf("enter binary number to convert to decimal: ");
scanf("%s", string);
for(s = strlen-1; s >= 0; s--)
{
if(string[s] == '1')
{
sum = sum + pow(2,s);
}
}
}
return 0;
答案 0 :(得分:1)
你可能想要strlen(string) - 1
,而不是strlen - 1
。我最好的猜测是你的程序将strlen
解释为一个函数指针,并且在此之后发生了疯狂的事情。
实际上,您可能会对strtol功能感兴趣,这似乎与您正在寻找的功能完全相同。
答案 1 :(得分:0)
您使用strlen作为整数。我认为你的意思是strlen(字符串)
答案 2 :(得分:0)
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <ctype.h>
#include <stdlib.h>
void reverse_string(char *string)
{
int string_length = strlen(string);
char temp;
int i;
for (i = 0; i < string_length/2; i++)
{
temp = string[i];
string[i] = string[string_length - (i + 1)];
string[string_length - (i + 1)] = temp;
}
}
int main()
{
char string[100];
int s;
char a;
char j;
int sum = 0;
int string_length = 0;
int number, original_number;
int remainder;
char binary_string[200];
int i = 0;
printf("B = B to D\n");
printf("D = D to B\n");
printf("choose which one to convert to:");
scanf("%c%c", &a, &j);
a = toupper(a);
if (a == 'B')
{
printf("enter binary number to convert to decimal: ");
scanf("%s", string);
string_length = strlen(string);
for(s = strlen(string)-1; s >= 0; s--)
{
if(string[s] == '1')
{
sum = sum + pow(2,string_length - (s + 1));
}
}
printf("%s in binary is %d\n",string,sum);
}
else if (a == 'D')
{
printf("enter positive decimal number to convert to binary: ");
scanf("%s",string);
number = atoi(string);
original_number = number;
if ( number < 0 )
{
printf("ERROR: only positive numbers please\n");
return 1;
}
do
{
remainder = number % 2;
if ( remainder == 0 )
binary_string[i] = '0';
else
binary_string[i] = '1';
number = number / 2;
i += 1;
}
while (number > 0);
binary_string[i] = '\0';
reverse_string(binary_string);
printf("decimal %d is %s in binary\n",original_number,binary_string);
}
return 0;
}
答案 3 :(得分:0)
for(sum=0, j=0, s=strlen(string)-1; s >= 0; s--, ++j){
if(string[s] == '1'){
sum = sum + pow(2,j);
}
}
printf("%d\n",sum);
答案 4 :(得分:0)
strlen使用不当。我想你想做像strlen(string)-1这样的事情。 BTW你的逻辑不能转换小数部分。检查此代码:
#include <stdio.h>
#define MAX 1000
int main()
{
double fraDecimal=0.0,dFractional=0.0 ,fraFactor=0.5;
long dIntegral = 0,bIntegral=0,bFractional[MAX];
long intFactor=1,remainder,i=0,k=0,flag=0;
char fraBinary[MAX];
printf("Enter any fractional binary number: ");
scanf("%s",&fraBinary);
while(fraBinary[i]) //Separating the integral and fractional parts
{
if(fraBinary[i] == '.')
flag = 1; //If dot is found start taking the fractional part.
else if(flag==0)
bIntegral = bIntegral * 10 + (fraBinary[i] -48);
/* char - 48 to get the numerical value.*/
else
bFractional[k++] = fraBinary[i] -48;
i++;
}
while(bIntegral!=0){
remainder=bIntegral%10;
dIntegral= dIntegral+remainder*intFactor;
intFactor=intFactor*2;
bIntegral=bIntegral/10;
}
for(i=0;i<k;i++){
dFractional = dFractional + bFractional[i] * fraFactor;
fraFactor = fraFactor / 2;
}
fraDecimal = dIntegral + dFractional ;
printf("Equivalent decimal value: %Lf",fraDecimal);
return 0;
}