可能重复:
In Python how do I sort a list of dictionaries by values of the dictionary?
我正在编写一个Python 3.2应用程序,我有一个包含以下内容的词典列表:
teamlist = [{ "name":"Bears", "wins":10, "losses":3, "rating":75.00 },
{ "name":"Chargers", "wins":4, "losses":8, "rating":46.55 },
{ "name":"Dolphins", "wins":3, "losses":9, "rating":41.75 },
{ "name":"Patriots", "wins":9, "losses":3, "rating": 71.48 }]
我希望列表按评级键中的值排序。我该如何做到这一点?
答案 0 :(得分:6)
使用operator.itemgetter
作为密钥:
sorted(teamlist, key=operator.itemgetter('rating'))
答案 1 :(得分:4)
您可以使用sorted
功能和排序键,指向您希望的任何字段。
teamlist_sorted = sorted(teamlist, key=lambda x: x['rating'])
答案 2 :(得分:1)
from operator import itemgetter
newlist = sorted(team_list, key=itemgetter('rating'))