我正在尝试提高应用程序的性能。我可能需要创建在cron上运行的汇总表,以便应用程序加载时间不会太长(5-10秒)。这是最好的主意吗?
鉴于下表:
mysql> describe school_data_sets_numeric_data;
+--------------+---------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+--------------+---------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| data_set_nid | int(11) | NO | MUL | NULL | |
| school_nid | int(11) | NO | MUL | NULL | |
| year | int(11) | NO | MUL | NULL | |
| description | varchar(255) | NO | | NULL | |
| value | decimal(18,5) | NO | | NULL | |
+--------------+---------------+------+-----+---------+----------------+
6 rows in set (0.00 sec)
以下查询(为学校的每个data_set_nid运行一次)
此查询快速运行(0秒):
SELECT year, description, CONCAT(FORMAT((value/(SELECT SUM(value)
FROM `school_data_sets_numeric_data` as numeric_data_inner
WHERE year = numeric_data_outer.year and data_set_nid = numeric_data_outer.data_set_nid and school_nid = numeric_data_outer.school_nid)) * 100, 2), '%') as value
FROM `school_data_sets_numeric_data` as numeric_data_outer
WHERE data_set_nid = 38251 and school_nid = 32805 ORDER BY id DESC;
说明:
+----+--------------------+--------------------+------+---------------------------------------------+--------------+---------+-----------------------------------------------------------------------------------------------------------+------+-----------------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+--------------------+--------------------+------+---------------------------------------------+--------------+---------+-----------------------------------------------------------------------------------------------------------+------+-----------------------------+
| 1 | PRIMARY | numeric_data_outer | ref | data_set_nid,data_set_nid_2,school_nid | data_set_nid | 8 | const,const | 17 | Using where; Using filesort |
| 2 | DEPENDENT SUBQUERY | numeric_data_inner | ref | year,data_set_nid,data_set_nid_2,school_nid | data_set_nid | 8 | rocdocs_main_drupal_7.numeric_data_outer.data_set_nid,rocdocs_main_drupal_7.numeric_data_outer.school_nid | 9 | Using where |
+----+--------------------+--------------------+------+---------------------------------------------+--------------+---------+-----------------------------------------------------------------------------------------------------------+------+-----------------------------+
此查询运行缓慢(1.43秒):
SELECT year, description, CONCAT(FORMAT((SUM(value)/(SELECT SUM(value)
FROM `school_data_sets_numeric_data` as numeric_data_inner
WHERE year = numeric_data_outer.year and data_set_nid = numeric_data_outer.data_set_nid)) * 100, 2), '%') as value
FROM `school_data_sets_numeric_data` as numeric_data_outer
WHERE data_set_nid = 38251 GROUP BY year,description ORDER BY id DESC;
说明:
+----+--------------------+--------------------+------+----------------------------------+----------------+---------+-------+-------+----------------------------------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+--------------------+--------------------+------+----------------------------------+----------------+---------+-------+-------+----------------------------------------------+
| 1 | PRIMARY | numeric_data_outer | ref | data_set_nid,data_set_nid_2 | data_set_nid_2 | 4 | const | 90640 | Using where; Using temporary; Using filesort |
| 2 | DEPENDENT SUBQUERY | numeric_data_inner | ref | year,data_set_nid,data_set_nid_2 | year | 4 | func | 38871 | Using where |
+----+--------------------+--------------------+------+----------------------------------+----------------+---------+-------+-------+----------------------------------------------+
答案 0 :(得分:-1)
相关的子查询/子选择通常是一个bottelneck - 部分原因是MySql只有一个嵌套的循环连接算法,没有散列连接/合并连接。
我会尝试将主选择加入到包含所需所有SUM值的派生表中。