Question

当我向服务器发送POST请求时，如果响应为200，我将获得JSON正文。但是对于不成功的请求，服务器发送400响应代码但我的android代码抛出FileNotFoundException。阅读400响应和200响应之间有什么区别吗？

        StringBuffer responseBuilder = new StringBuffer();
    String line = null;
    HttpURLConnection conn = null;
    OutputStream out = null;
    BufferedReader rd = null;
    System.setProperty("http.keepAlive", "false");
    try
    {
        conn = (HttpURLConnection) new URL(requestURL).openConnection();
        conn.setRequestMethod("POST");
        conn.setDoOutput(true);
        conn.setDoInput(true);
        conn.setUseCaches(false);
        conn.setAllowUserInteraction(false);
        conn.setConnectTimeout(NetworkConstants.CONNECTION_TIMEOUT);
        conn.setReadTimeout(NetworkConstants.SOCKET_TIMEOUT);

        out = conn.getOutputStream();
        Writer writer = new OutputStreamWriter(out, "UTF-8");
        String s = formatParams();
        Log.d("-------------------------------------------------->", s);
        writer.write(s);
        writer.flush();
        writer.close();
    }

    catch (Exception e)
    {

    }

    finally
    {
        if (out != null)
        {
            try
            {
                out.close();
            }
            catch (IOException e)
            {
                e.printStackTrace();

            }
        }
    }
    try
    {
        rd = new BufferedReader(new InputStreamReader(conn.getInputStream()));
        while ((line = rd.readLine()) != null)
        {
            responseBuilder.append(line);
            if (!rd.ready())
            {
                break;
            }
        }
    }
    catch (Exception e)
    {
        e.printStackTrace();
    }

    finally
    {
        if (conn != null)
        {
            conn.disconnect();
        }
    }

    String response = responseBuilder.toString();
    Log.d("@@@@@@@@@@@@@@@@@@@@@@@@@@@", response);
    return response;

亲切的问候，

Answer 1

使用getErrorStream()。来自docs：

如果HTTP响应表明发生了错误，getInputStream()将抛出IOException。使用getErrorStream()读取错误响应。可以使用getHeaderFields()以正常方式读取标题。

示例代码：

        httpURLConnection.connect();

        int responseCode = httpURLConnection.getResponseCode();
        if (responseCode >= 400 && responseCode <= 499) {
            Log.e(TAG, "HTTPx Response: " + responseCode + " - " + httpURLConnection.getResponseMessage());
            in = new BufferedInputStream(httpURLConnection.getErrorStream());
        }
        else {
            in = new BufferedInputStream(httpURLConnection.getInputStream());
        }

        BufferedReader reader = new BufferedReader(new InputStreamReader(in));
        String line = "";
        while ((line = reader.readLine()) != null) {
            urlResponse.append(line);
        }

Answer 2

如果响应代码不是200或2xx，请使用getErrorStream（）而不是getInputStream（）来解析json并显示后端提供的消息。

Answer 3

我知道问这个问题已经有很长时间了，但是为了其他仍然遇到这种问题的人的利益，请注意，另一个可能导致该问题的原因是使用“ connection.getContent（）”来获取InputStream。
像这样：

InputStream is = (InputStream) connection.getContent();

这会造成一个问题，即根本不会处理大于399的响应代码。
因此建议像前面的注释中所示和以下示例中所示，直接与getInputStream（）和getErrorStream（）一起使用：

    HttpURLConnection connection = null;
    BufferedReader bufferedReader = null;
    try {
        String urlString = "http://www.someurl.com";
        URL url = new URL(urlString);
        connection = (HttpURLConnection) url.openConnection();
        connection.connect();
        InputStream is;
        int responseCode = connection.getResponseCode();
        if (responseCode < HttpURLConnection.HTTP_BAD_REQUEST) {
            is = connection.getInputStream();
        } else {
            is = connection.getErrorStream();
        }

        StringBuilder response = new StringBuilder();
        bufferedReader = new BufferedReader(new InputStreamReader(is));
        String tempLine;
        while ((tempLine = bufferedReader.readLine()) != null) {
            response.append(tempLine);
        }
        String serverResponse = response.toString();
    } catch (IOException e) {
        e.printStackTrace();
    } finally {
        if (bufferedReader != null) {
            try {
                bufferedReader.close();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
        if (connection != null) {
            connection.disconnect();
        }
    }

Android POST请求400响应代码抛出异常

3 个答案: