Question

我有一个增加数量的按钮，当我点按它时，我会拨打服务电话。问题是，如果我多次点击它，我只想在点击它之后进行服务调用。我尝试使用UITapGestureRecognizer，但我不知道如何计算水龙头的数量。

任何帮助都将不胜感激。

以下是示例代码

- (void)quantityChanged:(UITapGestureRecognizer *)tapRecognizer {
    static NSUInteger numberOfTaps;
    if (tapRecognizer.state == UIGestureRecognizerStateBegan) {
       numberOfTaps = 0;
    }
    if (tapRecognizer.state == UIGestureRecognizerStateEnded)
        NSLog(@"%d",numberOfTaps);
    if (tapRecognizer.state == UIGestureRecognizerStateChanged)
        numberOfTaps++;

}

Answer 1

四种可能的解决方案

我觉得你的方法很好

- (void)quantityChanged:(UITapGestureRecognizer *)tapRecognizer {

    static NSUInteger numberOfTaps;


   if (tapRecognizer.state == UIGestureRecognizerStateEnded) {

        numberOfTaps ++;

        NSLog(@"web service call with %d",numberOfTaps);
    }

}

查看日志

web service call with 1
web service call with 2
web service call with 3
web service call with 4

或

在触发之后移除quantityChanged UITapGestureRecognizer

我的意思是，从发件人对象中删除UITapGestureRecognizer（在第一次网络服务之后的quantityChanged方法内）

然后在您收到第一个网络服务响应后，再次将UITapGestureRecognizer添加到发件人。

或

使用UILongPressGestureRecognizer。这是一个漫长的事件过程。请检查事件状态是否已启动，已完成等，并编写代码。

- (IBAction)longPressDetected:(UIGestureRecognizer *)gestureRecognizer {        

    if (gestureRecognizer.state == UIGestureRecognizerStateBegan){

        NSLog(@"Long press began");

    } else if ( gestureRecognizer.state == UIGestureRecognizerStateRecognized ) {

            NSLog(@"Long press UIGestureRecognizerStateRecognized");
    }
    else if (gestureRecognizer.state == UIGestureRecognizerStateEnded) {

        NSLog(@"Long press Ended");
    }
    else {

        NSLog(@"Long press detected.");
    }       
}

或

为UITapGestureRecognizer设置 numberOfTapsRequired

UITapGestureRecognizer *doubleTapRecognizer = [[[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(beginComicTransitions:)] autorelease];    
doubleTapRecognizer.numberOfTapsRequired = 2;
doubleTapRecognizer.numberOfTouchesRequired = 1;
doubleTapRecognizer.delegate = self;

Answer 2

即使我怀疑这会导致实用的用户界面...如果您对用户可以“放入”的最大数量有所了解，您可以选择几个依赖于每个手势的手势监听器。其他- (void)requireGestureRecognizerToFail:(UIGestureRecognizer *)otherGestureRecognizer（doc here）。

代码可能如下所示：

-(void)addGestureRecognizers
{
  int maxCount = 10;
  UITapGestureRecognizer *other = nil;
  for(int i = maxCount; i < 0; i--)
  {
    UITapGestureRecognizer *tapper = [[UITapGestureRecognizer alloc]initWithTarget:self action:@selector(tapped:)];
    tapper.numberOfTapsRequired = i;
    if(other)
    {
      [tapper requireGestureRecognizerToFail:other]; 
    }
    [self.view addGestureRecognizer:tapper];
    other = tapper;
  }
}

-(void)tapped:(UITapGestureRecognizer *)tapper
{
  [self callWebservice:tapper.numberOfTapsRequired];
}

我没有测试它，从未使用过它，但这就是我从文档中理解的内容。

Answer 3

确定。所以我找到了解决问题的方法。我将以0.5秒的延迟执行我的Web服务调用，每次按下我的按钮时，我将取消所有等待执行的选择器并再次调用performSelector：withDelay。

Answer 4

没有UITapGestureOrganizer，就更容易了。

button.addTarget(self, action: #selector(multipleTap(_:event:)), for: UIControlEvents.touchDownRepeat)

然后：

func multipleTap(_ sender: UIButton, event: UIEvent) {
    let touch: UITouch = event.allTouches!.first!
    if touch.tapCount == 3 {
        print("triple tap")
    }
}

使用UITapGestureRecognizer计算点击次数

4 个答案: