我是python的新手,最近我使用Python和Sqlite3使用tkinter创建字典。 当我运行代码时,它在IDLE中返回多行,但在GUI中它只显示最后的结果。我想在GUI中显示所有信息。感谢您的任何帮助和建议。
import tkinter
import sqlite3
class Dictionary:
def __init__(self,master =None):
self.main_window = tkinter.Tk()
self.main_window.title("Lai Mirang Dictionary")
self.main_window.minsize( 600,400)
self.main_window.configure(background = 'paleturquoise')
self.frame1 = tkinter.Frame()
self.frame2= tkinter.Frame(bg = 'red')
self.frame3 =tkinter.Text( foreground = 'green')
self.frame4 = tkinter.Text()
self.lai_label = tkinter.Label(self.frame1,anchor ='nw',font = 'Times:12', text = 'Lai',width =25,borderwidth ='3',fg='blue')
self.mirang_label = tkinter.Label(self.frame1,anchor ='ne',font = 'Times:12', text = 'Mirang',borderwidth ='3',fg ='blue')
self.lai_label.pack(side='left')
self.mirang_label.pack(side = 'left')
self.kawl_buttom= tkinter.Button(self.frame2 ,fg = 'red',font = 'Times:12',text ='Kawl',command=self.dic,borderwidth ='3',)
self.lai_entry = tkinter.Entry(self.frame2, width= 28, borderwidth ='3',)
self.lai_entry.focus_force()
self.lai_entry.bind('<Return>', self.dic,)
self.lai_entry.configure(background = 'khaki')
self.lai_entry.pack(side='left')
self.kawl_buttom.pack(side = 'left')
self.value = tkinter.StringVar()
self.mirang_label= tkinter.Label(self.frame3,font = 'Times:12',fg = 'blue',textvariable = self.value,justify = 'left',wraplength ='260',width = 30, height = 15,anchor = 'nw')
self.mirang_label.pack()
self.mirang_label.configure(background = 'seashell')
self.copyright_label = tkinter.Label(self.frame4,anchor ='nw',font = 'Times:12:bold',text = "copyright @ cchristoe@gmail.com",width = 30,borderwidth = 3, fg = 'purple',)
self.copyright_label.pack()
self.frame1.pack()
self.frame2.pack()
self.frame3.pack()
self.frame4.pack()
tkinter.mainloop()
self.main_window.quit()
def dic(self, event = None):
conn = sqlite3.connect('C:/users/christoe/documents/sqlite/laimirangdictionary.sqlite')
c = conn.cursor()
kawl = self.lai_entry.get()
kawl = kawl + '%'
c.execute("SELECT * FROM laimirang WHERE lai LIKE ?", (kawl,))
c.fetchall
for member in c:
out = (member)
self.value.set(out)
print(out, )
dic=Dictionary()
答案 0 :(得分:0)
您需要更改:
c.execute("SELECT * FROM laimirang WHERE lai LIKE ?", (kawl,))
c.fetchall
for member in c:
out = (member)
self.value.set(out)
print(out, )
要:
for member in c.execute("SELECT * FROM laimirang WHERE lai LIKE ?", (kawl,)):
current_text = self.value.get()
new_text = current_text +( "\n" if current_text else "") +" ".join(member)
self.value.set(new_text)
新版本获取StringVar
值的当前值,然后在返回的结果中附加返回的结果,其中每行返回的行都在其自己的行上。然而,您所做的只是将StringVar
更新为当前成员对象,因此它只有最后一个值。
这是多行的看法: