paginate_alphabetically gem:命名空间中的分页链接不起作用

时间:2012-08-14 22:46:14

标签: ruby-on-rails ruby-on-rails-3 namespaces pagination routes

我在rails 3.2 app中有一个admin命名空间。我想在https://github.com/edendevelopment/paginate_alphabetically使用paginate_alphabetically gem分页作者的postgres数据库。

app / controllers / admin中的控制器(类Admin :: AuthorsController< AdminController)具有:

def index
    @authors = Author.includes(:stories).alphabetical_group(params[:letter])
    respond_to do |format|
        format.html # show.html.erb
        format.json { render json: @authors }
    end
end

app / models中的author.rb模型具有: paginate_alphabetically:by => :姓氏

作者在app / views / admin / index.html.erb中查看了:

<ul class='pagination'>
<%- Author.pagination_letters.each do |letter| -%>
<li><%= link_to(letter, admin_authors_path(:letter => letter)) %></li>
<%- end -%>
</ul>

这似乎生成了正确的html,其中包含:

<ul class='pagination'>
<li><a href="/admin/authors?letter=A">A</a></li> 
...etc.
</ul>

但点击时链接不会出现在任何地方。 ruby输出如下:

Started GET "/admin/authors?letter=A" for 127.0.0.1 at 2012-08-14 18:18:15 -0400
Processing by Admin::AuthorsController#index as JS
Parameters: {"letter"=>"A", "collection"=>{"list"=>:get}}
Author Load (1.8ms)  SELECT "authors".* FROM "authors" 
Author Load (0.7ms)  SELECT "authors".* FROM "authors" WHERE (LOWER(last_name) LIKE     
'a%') ORDER BY last_name
Story Load (0.6ms)  SELECT "stories".* FROM "stories" INNER JOIN "authors_stories" ON   
"stories"."id" = "authors_stories"."story_id" WHERE "authors_stories"."author_id" = 1
Story Load (0.8ms)  SELECT "stories".* FROM "stories" INNER JOIN "authors_stories" ON "stories"."id" = "authors_stories"."story_id" WHERE "authors_stories"."author_id" = 2
 Story Load (67.1ms)  SELECT "stories".* FROM "stories" INNER JOIN "authors_stories" ON "stories"."id" = "authors_stories"."story_id" WHERE "authors_stories"."author_id" = 3
 Story Load (1.1ms)  SELECT "stories".* FROM "stories" INNER JOIN "authors_stories" ON "stories"."id" = "authors_stories"."story_id" WHERE "authors_stories"."author_id" = 4
 Story Load (1.2ms)  SELECT "stories".* FROM "stories" INNER JOIN "authors_stories" ON "stories"."id" = "authors_stories"."story_id" WHERE "authors_stories"."author_id" = 5
 Rendered admin/authors/_authors.html.erb (131.6ms)
 Rendered admin/authors/index.html.erb within layouts/admin (149.5ms)

在171ms完成200 OK(浏览次数:96.4ms | ActiveRecord:73.3ms)

当我实际输入网址localhost:3000 / admin / authors?letter = A(或任何其他字母)时,我会得到一个包含我想要的页面,一个按字母顺序排列的按字母顺序排列的作者列表。它只是不适用于上述链接。

在我的routes.rb文件中,我有:

namespace :admin do
  resources :authors
  resources :issues
  resources :stories  
  root :to => 'authors#index
end

思想?

0 个答案:

没有答案