我的后端有一个简单的用户管理器,我希望能够在不设置新密码/每次重复旧密码的情况下编辑用户。
现在,如果我在编辑用户时将密码字段留空,symfony2会抱怨必须输入密码,当然我在注册新用户时需要此功能,但是当我编辑它们时,我想要如果没有填写密码框,则忽略密码框。
这是如何完成的?
答案 0 :(得分:26)
对于其他人的参考,我是这样做的。
我的formType:
public function buildForm(FormBuilder $builder, array $options)
{
$builder
->add('username', 'text', array('label' => 'Servernamn '))
->add('plainPassword', 'repeated', array('type' => 'password', 'first_name' => 'Lösenord för server ', 'second_name' => 'Upprepa lösenord för server',));
$builder-> addValidator(new CallbackValidator(function(FormInterface $form){
$username = $form->get('username')->getData();
if (empty($username)) {
$form['username']->addError(new FormError("Du måste ange ett namn för servern"));
}
}));
}
我的updateAction:
public function updateServerAction($id)
{
$em = $this->getDoctrine()->getEntityManager();
$entity = $em->getRepository('BizTVUserBundle:User')->find($id);
if (!$entity) {
throw $this->createNotFoundException('Unable to find Container entity.');
}
$originalPassword = $entity->getPassword();
$editForm = $this->createForm(new editServerType(), $entity);
$request = $this->getRequest();
$editForm->bindRequest($request);
if ($editForm->isValid()) {
$plainPassword = $editForm->get('plainPassword')->getData();
if (!empty($plainPassword)) {
//encode the password
$encoder = $this->container->get('security.encoder_factory')->getEncoder($entity); //get encoder for hashing pwd later
$tempPassword = $encoder->encodePassword($entity->getPassword(), $entity->getSalt());
$entity->setPassword($tempPassword);
}
else {
$entity->setPassword($originalPassword);
}
$em->persist($entity);
$em->flush();
return $this->redirect($this->generateUrl('Server'));
}
因此,应该设置更新我的用户密码,否则保留原始密码。
答案 1 :(得分:14)
在您的密码属性的实体设置器上,使其如下所示:
/**
* Set password
*
* @param string $password
* @return User
*/
public function setPassword($password)
{
if (!is_null($password)) {
$this->password = $password;
}
return $this;
}
诀窍是检查传递的参数是否为空,只检查它是否为空。
答案 2 :(得分:4)
如果您需要在$ options数组中添加必需选项。例如:
public function buildForm(FormBuilder $builder, array $options)
{
$builder
->add('username', 'text', array('label' => 'Servernamn '))
->add('plainPassword', 'repeated', array(
'type' => 'password',
'first_name' => 'password',
'second_name' => 'repeat_password',
'required' => false,
));
}
答案 3 :(得分:2)
我所做的是按原样离开UserType
,只删除控制器中的密码字段:
/**
* @Route("/users/edit/{username}", name="user_edit")
*/
public function editAction(Request $request, User $user)
{
$form = $this->createForm(UserType::class, $user);
// Remove the password field when editing the user
// Otherwise it must be entered each time the user is edited
// We can change the password via a special edit-user-password page
$form->remove('password');
$form->handleRequest($request);
if ($form->isValid()) {
// ...
}
}
这样你就可以拥有一个UserType,可以在editAction和newAction中重用。
请务必在$form->remove('password');
之前添加行$form->handleRequest($request);
。
答案 4 :(得分:1)
有一篇文章提供了许多选项来实现您的请求,来自Symfony2食谱,特别是下面的部分为我工作:
Customizing your Form based on the underlying Data
以下是实施:
public function buildForm(FormBuilderInterface $builder, array $options)
{
// ...
$builder->addEventListener(FormEvents::PRE_SET_DATA, function(FormEvent $event) {
$product = $event->getData();
$form = $event->getForm();
// check if the Product object is "new"
// If no data is passed to the form, the data is "null".
// This should be considered a new "Product"
if (!$product || null === $product->getId()) {
$form->add('name', 'text');
}
});
}
答案 5 :(得分:0)
对于验证,使用2个不同的验证组,并通过可调用函数设置正确的验证组。
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder->add(
'oldPassword',
PasswordType::class,
[
'constraints' => new UserPassword([
'groups' => 'profile_password',
]),
'mapped' => false,
'required' => false,
]
);
$builder->add(
'plainPassword',
PasswordType::class,
[
'constraints' => new NotBlank([
'groups' => 'profile_password',
]),
'mapped' => false,
'required' => false,
]
);
}
/**
* {@inheritdoc}
*/
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults(
[
'validation_groups' => function (FormInterface $form) {
$newPassword = $form->get('plainPassword')->getData();
$oldPassword = $form->get('oldPassword')->getData();
if ($oldPassword || $newPassword) {
return ['profile', 'profile_password'];
} else {
return ['profile'];
}
},
]
);
}
答案 6 :(得分:0)
Symfony 5方法:
在控制器类中:
/**
* @Route("/user/{id}/edit")
*/
public function updateUser(
$id, // See 'Route' annot., needed to `find()` User, adjust to your needs
User $user,
Request $request,
UserPasswordEncoderInterface $passwordEncoder,
UserRepository $userRepository
): Response {
$form = $this->createForm(UserFormType::class, $user);
// if password field is required by default, we have to `add()` it again
// with `required` set to `false`
$form->add(
'plainPassword',
PasswordType::class,
[
// do not use Constraint NotBlank()
'required' => false,
'mapped' => false
]
);
$form->handleRequest($request);
if ($form->isSubmitted() && $form->isValid()) {
$entity = $userRepository->find($id); // as above, adjust to your needs
if (!$entity) {
throw $this->createNotFoundException('User does not exist!');
}
$originalPassword = $entity->getPassword();
/** @var User $user */
$user = $form->getData();
// keep original password if new one isn't provided
if (!empty($form['plainPassword']->getData())) {
$user->setPassword(
$passwordEncoder->encodePassword(
$user,
$form['plainPassword']->getData()
)
);
} else {
// set old password
$user->setPassword($originalPassword);
}
$em = $this->getDoctrine()->getManager();
$em->persist($user);
$em->flush();
return new Response('User updated!');
}
return $this->render(
'admin/user_edit.html.twig',
[
'requestForm' => $form->createView(),
]
);
}
答案 7 :(得分:-3)
你可以用
做点什么if (empty($password)) {
//edit the password
}
尝试将其修复到表单的PHP中。