Question

我编写了一个简单的路由，它将获取任何http请求并将其保存在file：output中。保存后，将创建一个可读取所有请求的处理器。

这是我的代码：

import org.apache.camel.CamelContext;
import org.apache.camel.Exchange;
import org.apache.camel.processor.*;
import org.apache.camel.builder.RouteBuilder;
import org.apache.camel.impl.DefaultCamelContext;


public class LoadBalancer {
   public static void main(String args[]) throws Exception {
          CamelContext context = new DefaultCamelContext();

        context.addRoutes(new RouteBuilder() {

            public void configure() {
                from("jetty://http://localhost:8080")
                .to("file:output");
                from("file://output").process(new processor()
                {
                    public void process(Exchange e)
                    {
                        System.out.println("Recieved exchange:" + e.getIn());
                    }
                }
                );
                //.loadBalance().roundRobin().to("http://172.28.39.138:8080","http://172.168.20.118:8080");
            }
        }); 

        context.start();

        Thread.sleep(100000);  
        context.stop();
    }
 }

现在当我编译它时，我收到以下错误：

 Exception in thread "main" java.lang.Error: Unresolved compilation problems: 
    The method process(Processor) in the type ProcessorDefinition<RouteDefinition> is not applicable for the arguments (new processor(){})
    processor cannot be resolved to a type

On the line `from("file://output").process(new processor()`



I couldn't figure out what kind of error it it.
    Am I doing anything wrong in the code?
    Any help would be very much appreciated.

    Cheers!!

Answer 1

内联Processors应该像这样写......

from("file://output").process(new Processor() {
    public void process(Exchange exchange) throws Exception {
        System.out.println("Recieved exchange:" + e.getIn());
   }
});

Apache camel错误：方法过程不适用于参数

1 个答案: