Question

我关注：http://framework.zend.com/manual/en/learning.quickstart.create-model.html。

在问题之后继续撞墙。我目前的错误是：

An error occurred

Application error

Exception information:

Message: A table must have a primary key, but none was found

Stack trace:

#0 C:\wamp\www\zendtest\quickstart\library\Zend\Db\Table\Abstract.php(982): Zend_Db_Table_Abstract->_setupPrimaryKey()
#1 C:\wamp\www\zendtest\quickstart\library\Zend\Db\Table\Select.php(100): Zend_Db_Table_Abstract->info()
#2 C:\wamp\www\zendtest\quickstart\library\Zend\Db\Table\Select.php(78): Zend_Db_Table_Select->setTable(Object(Application_Model_DbTable_Guestbook))
#3 C:\wamp\www\zendtest\quickstart\library\Zend\Db\Table\Abstract.php(1018): Zend_Db_Table_Select->__construct(Object(Application_Model_DbTable_Guestbook))
#4 C:\wamp\www\zendtest\quickstart\library\Zend\Db\Table\Abstract.php(1326): Zend_Db_Table_Abstract->select()
#5 C:\wamp\www\zendtest\quickstart\application\models\GuestbookMapper.php(58): Zend_Db_Table_Abstract->fetchAll()
#6 C:\wamp\www\zendtest\quickstart\application\controllers\GuestbookController.php(14): Application_Model_GuestbookMapper->fetchAll()
#7 C:\wamp\www\zendtest\quickstart\library\Zend\Controller\Action.php(516): GuestbookController->indexAction()
#8 C:\wamp\www\zendtest\quickstart\library\Zend\Controller\Dispatcher\Standard.php(295): Zend_Controller_Action->dispatch('indexAction')
#9 C:\wamp\www\zendtest\quickstart\library\Zend\Controller\Front.php(954): Zend_Controller_Dispatcher_Standard->dispatch(Object(Zend_Controller_Request_Http), Object(Zend_Controller_Response_Http))
#10 C:\wamp\www\zendtest\quickstart\library\Zend\Application\Bootstrap\Bootstrap.php(97): Zend_Controller_Front->dispatch()
#11 C:\wamp\www\zendtest\quickstart\library\Zend\Application.php(366): Zend_Application_Bootstrap_Bootstrap->run()
#12 C:\wamp\www\zendtest\quickstart\public\index.php(26): Zend_Application->run()
#13 {main}  
Request Parameters:

array (
  'controller' => 'guestbook',
  'action' => 'index',
  'module' => 'default',
)

但我确信我的表有一个表的主键代码：

CREATE TABLE guestbook (
    id INTEGER NOT NULL PRIMARY KEY AUTOINCREMENT,
    email VARCHAR(32) NOT NULL DEFAULT 'noemail@test.com',
    comment TEXT NULL,
    created DATETIME NOT NULL
);

CREATE INDEX "id" ON "guestbook" ("id");

不明白为什么会收到错误

Answer 1

在Zend Framework中，所有表都应具有主键列。在您的模型中，您应该设置主列的名称。

例如，表用户：

class Application_Model_TableUser extends Zend_Db_Table_Abstract
{
    protected $_name = 'user'; // table name
    protected $_primary = 'id'; // primary column name
}

Answer 2

我得到了同样的错误。我发现Zend缓存了DB元数据（显然是出于性能原因）。在我的情况下，我删除并创建了一个具有相同名称的表。新表有一个主要列，而旧表没有。删除Zend缓存为我解决了这个问题。

zend Framework快速入门表必须具有主键，但未找到任何主键

2 个答案: