如何在WPF中以编程方式将数据项添加到DataGrid
哪些没有绑定? DataGrid
有4列。
答案 0 :(得分:14)
目前还不是很清楚,你喜欢做什么。我想,你已经定义了一个你想放置DataGrid的地方。为了便于说明,我创建了一个新的WPF项目并使用chridram提供的代码,该代码发布了第一个答案。
在下面的MainWindow.xaml中,我将Grid MainGrid命名为在后面的代码中访问它:
<Window x:Class="WpfExperiments.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="MainWindow" Height="350" Width="525">
<Grid Name="MainGrid"/>
</Window>
DataItem类不是WPF类,而是由Yourself创建的自定义类:
public class DataItem
{
public string Column1 { get; set; }
public string Column2 { get; set; }
public string Column3 { get; set; }
public string Column4 { get; set; }
}
要让DataGrid以编程方式显示存储在DataItem对象中的数据,您可以执行以下操作:
public partial class MainWindow : Window
{
public MainWindow()
{
InitializeComponent();
// Your programmatically created DataGrid is attached to MainGrid here
var dg = new DataGrid();
this.MainGrid.Children.Add(dg);
// create four columns here with same names as the DataItem's properties
for (int i = 1; i <= 4; ++i)
{
var column = new DataGridTextColumn();
column.Header = "Column" + i;
column.Binding = new Binding("Column" + i);
dg.Columns.Add(column);
}
// create and add two lines of fake data to be displayed, here
dg.Items.Add(new DataItem { Column1 = "a.1", Column2 = "a.2", Column3 = "a.3", Column4 = "a.4" });
dg.Items.Add(new DataItem { Column1 = "b.1", Column2 = "b.2", Column3 = "b.3", Column4 = "b.4" });
}
}
我希望这会有所帮助。
问候 约尔格
答案 1 :(得分:2)
这是一个用于从数据库中检索数据的函数
, '%Y-%m-%d' )
SELECT a.id, a.clientId, a.enrollDate, a.cancelDate FROM gap_borrower a WHERE STR_TO_DATE( a.`loanEndDate` , '%Y-%m-%d' ) >= STR_TO_DATE( '2015-12-31', '%Y-%m-%d' ) AND FIND_IN_SET( a.status, 'A,C' ) AND (CASE WHEN a.cancelDate IS NOT NULL THEN (STR_TO_DATE( a.`enrollDate` , '%Y-%m-%d' ) <> STR_TO_DATE( a.cancelDAte, '%Y-%m-%d' )) END )
答案 2 :(得分:0)
.xaml:
<DataGrid x:Name="dataGrid" Margin="10">
<DataGrid.Columns>
<DataGridCheckBoxColumn Binding="{Binding Path=Column1}"/>
<DataGridTextColumn Binding="{Binding Path=Column2}"/>
</DataGrid.Columns>
</DataGrid>
.cs:
public class DataItem
{
public bool Column1 { get; set; }
public string Column2 { get; set; }
}
/// <summary>
/// Interaction logic for MainWindow.xaml
/// </summary>
public partial class MainWindow : Window
{
public MainWindow()
{
InitializeComponent();
}
private void Window_Loaded(object sender, RoutedEventArgs e)
{
DataItem item = new DataItem();
item.Column1 = true;
item.Column2 = "test";
dataGrid.Items.Add(item);
}
}