Question

我已经设法使这几乎工作，但我认为我得到了一些严重的困惑。所有示例似乎都涵盖了根据其ID发现单个记录。

我以为我可以传递一个参数来过滤单个属性

https://xxxx.basecamphq.com/companies.xml?name=xxxx

Basecamp :: Company.find（：all，：params =＆gt; {：name =＆gt; xxx}）

require 'rubygems'
require 'English'
require 'trollop'
require 'basecamp'
require 'ap'

opts = Trollop::options do
    version "1.0"
    banner <<-EOS
    #{File.basename($0)}
    Description: Dump the users from a company stored in basecampe via the api.

    Usage:
           #{File.basename($0)} [options]
    where [options] are:
    EOS
    opt :company , "Company to export" , :default => "XXXX"
    opt :token_file, "File to read token from " , :default => "~/.basecamp/token"
end


basecamp_token = IO.read(File.expand_path(opts[:token_file])).chomp

Basecamp.establish_connection!('xxxx.basecamphq.com', basecamp_token , 'X' , true)

#Work out company id from company name
company = Basecamp::Company.find(:all).select { |c| c.attributes["name"] == opts[:company] }
company_id = company[0].instance_variable_get("@attributes")["id"]

people = Basecamp::Person.find(:all, :params => {:company_id => company_id })
#ap people

#todo work out how to iterate over all people
puts people[0].instance_variable_get("@attributes")["email_address"]

Answer 1

事实证明：首先会按照我的意愿返回一家公司，但是我没有找到合乎逻辑的方法，因为我不想要第一个条目，我想要任何符合我的参数的条目..

#Work out company id from company name
company = Basecamp::Company.find(:first, :params => {:name => opts[:company] })
people = Basecamp::Person.find(:all, :params => {:company_id => company.id })

people.each do | person |
    puts person.email_address
end

如何使用basecamp API返回与公司关联的所有电子邮件地址的列表

1 个答案: