我一直收到以下错误
错误:错误:语法错误,无法识别的表达式:table $ MainContent $ gridPlans $ ctl02 $ chkSelected 源文件:http://code.jquery.com/jquery-latest.min.js 行:2
我已经处理了脚本的哪个部分导致了这个问题,但不确定如何解决它:
// Check Box selector
$("input:checkbox:not(:checked)").each(function () {
var column = "table ." + $(this).attr("name"); // this line is not working
$(column).hide();
});
$("input:checkbox").click(function () {
var column = "table ." + $(this).attr("name");
$(column).toggle();
});
// Manage column checkboxes that should be unchecked
function manChecks() {
var __CS = document.getElementById('__CS');
var cols = __CS.value; // this line also causing issues
colManage(1, cols.indexOf('|1') != -1);
colManage(2, cols.indexOf('|2') != -1);
colManage(3, cols.indexOf('|3') != -1);
colManage(5, cols.indexOf('|5') != -1);
colManage(6, cols.indexOf('|6') != -1);
colManage(7, cols.indexOf('|7') != -1);
colManage(8, cols.indexOf('|8') != -1);
colManage(9, cols.indexOf('|9') != -1);
}
function colManage(id, show) {
document.getElementById(id).checked = show;
var column = "table ." + id;
if (show) {
$(column).show();
$('label[for=' + id + ']').addClass('checked')
}
else {
$(column).hide();
$('label[for=' + id + ']').removeClass('checked')
}
}
答案 0 :(得分:5)