Question

我有一个像

这样的字符串数组

urls_parts=['week', 'weeklytop', 'week/day']

我需要在我的网址中监控这些字符串的包含，所以这个例子只需要由每周顶部分触发：

url='www.mysite.com/weeklytop/2'
for part in urls_parts:
    if part in url:
       print part

但它当然也是由'周'引发的。这样做的方法是什么？

OOps，让我指一下我的问题。当url ='www.mysite.com / week / day / 2'和part ='week'时，我需要不触发该代码需要触发的唯一网址是当part ='week'和url ='www.mysite.com / week / 2'或'www.mysite.com/week/2-second'时，例如

Answer 1

我就是这样做的。

import re
urls_parts=['week', 'weeklytop', 'week/day']
urls_parts = sorted(urls_parts, key=lambda x: len(x), reverse=True)
rexes = [re.compile(r'{part}\b'.format(part=part)) for part in urls_parts]

urls = ['www.mysite.com/weeklytop/2', 'www.mysite.com/week/day/2', 'www.mysite.com/week/4']
for url in urls:
    for i, rex in enumerate(rexes):
        if rex.search(url):
            print url
            print urls_parts[i]
            print
            break

<强>输出

www.mysite.com/weeklytop/2
weeklytop

www.mysite.com/week/day/2
week/day

www.mysite.com/week/4
week

按长度排序的建议来自@Roman

Answer 2

按照len和break从第一场比赛的循环中对您进行排序。

Answer 3

尝试这样的事情：

>>> print(re.findall('\\weeklytop\\b', 'www.mysite.com/weeklytop/2'))
['weeklytop']
>>> print(re.findall('\\week\\b', 'www.mysite.com/weeklytop/2'))
[]

程序：

>>> urls_parts=['week', 'weeklytop', 'week/day']
>>> url='www.mysite.com/weeklytop/2'
>>> for parts in urls_parts:
    if re.findall('\\'+parts +r'\b', url):
        print (parts)

输出：

weeklytop

Answer 4

为什么不这样使用urls_parts？

 ['/week/', '/weeklytop/', '/week/day/']

Answer 5

您的代码稍有变化就可以解决此问题 -

>>> for part in urls_parts:
        if part in url.split('/'):              #splitting the url string with '/' as delimiter
            print part

    weeklytop

python中的字符串比较

5 个答案: