我陷入了小问题。有一个名为Table_Activities的表。
Table_Activities (Act_id
,Dat
e,Activity_name
,description
)。
我们需要生成一份报告。用户将从下拉列表中选择要为其生成报告的月和年。
我们需要按活动名称显示该月份和年份组的所有活动。
示例 - 用户选择六月和 2012 。
报告将是 -
园艺
01/06/2012 - They have planted 100 trees.
14/06/2012 - something
27/06/2012 - something
培训
02/06/2012 - Detail description
15/06/2012 - something
28/06/2012 - something
我的问题是以这种格式获取数据的mysql查询是什么?
答案 0 :(得分:1)
要按Activity_name获取特定月份和年份组的数据,请尝试以下操作:
SELECT Activity_name
,GROUP_CONCAT(DATE_FORMAT(Date,"%d/%m/%Y")) as `Date`
,GROUP_CONCAT(Description) as `Description`
FROM Table_Activities
WHERE MONTH(Date) = MONTH('2012-06-01')
AND YEAR(Date) = YEAR('2012-06-01')
GROUP BY Activity_name
<强>输出强>
ACTIVITY_NAME DATE DESCRIPTION ----------------------------------------------------------------------------------- Gardening 01/06/2012,27/06/2012 They have planted 100 trees.,Description3 Training 12/06/2012,28/06/2012 Description2,Description4
答案 1 :(得分:1)
select `Date`,description from tm_activities
where month(`Date`)='6' and year(`Date`)='2012'
order by Activity_name,`date`
要返回问题中指明的确切格式,请尝试以下操作:
select concat(if(actdate='',activity_name,date_format(actdate,'%d/%m/%y')),if(description<>'',concat(' - ',description),'')) as labelm from
(
(select ActDate,description,activity_name from tm_activities where month(ActDate)='6' and year(ActDate)='2012'
)
union all
(Select distinct '','',activity_name from tm_activities where month(ActDate)='6' and year(ActDate)='2012')
)m order by activity_name,actdate
;
输出如下:
Gardening
01/06/12 - They have planted 100 trees.
27/06/12 - Gar 2
Training
12/06/12 - Training 1
28/06/12 - Traning 2
30/06/12 - Traning 3
答案 2 :(得分:0)
Select
DATE_FORMAT('date_column',"%D/%M/%Y") as `Date`,
other_column
from Table_Activities
where Month(Date) = Month('2012-06-01')
AND Year(Date) = Year('2012-06-01')