Question

对于我的部分申请，我需要在选择该选项时显示所有联系人（包括电话号码）的列表。

以下是按下按钮时调用的活动：

package com.example.prototype01;

import android.app.Activity;
import android.database.Cursor;
import android.os.Bundle;
import android.provider.ContactsContract;
import android.util.Log;

public class nominateContactsActivity extends Activity {
    public void onCreate(Bundle savedInstanceState){
        super.onCreate(savedInstanceState);
        setContentView(R.layout.nominatecontactslayout);
        Cursor c = getContentResolver().query(ContactsContract.Contacts.CONTENT_URI, null, null, null, null);
        String contactName, contactTelNumber = "";
        String contactID;
        c.moveToFirst();
        for (int i = 0; i < c.getCount(); i++) {
            contactName = c.getString(c.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
            contactID = c.getString(c.getColumnIndex(ContactsContract.Contacts._ID));
            if (Integer.parseInt(c.getString(c.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
                Cursor pCur = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?", new String[] { contactID },null);
                while (pCur.moveToNext()) {
                    contactTelNumber = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                } 
            }
            Log.i("name ", contactName + " ");
            Log.i("number ", contactTelNumber + " ");
            c.moveToNext();

        }
    }
    }

如您所见，此代码返回手机上存储的所有联系人的姓名和电话号码。目前，这些只是简单地回应到logcat。我似乎无法弄清楚如何在列表视图中列出这些项目，只显示名称和数字。我已经按照几个教程无济于事，所以我很不情愿地寻求你的帮助。我不情愿地说，因为我确信这个问题已被多次回答，我似乎无法将解决方案应用到我的代码中！

提前谢谢!!

亲切的问候， Antwan

Answer 1

以下是我将联系人放入listView

的方法

在您的活动中：

private ListView mContactsListView;
private ListContactItemAdapter mContactsListAdapter;

this.mContactsListAdapter = new ListContactItemAdapter(this, R.layout.contact_row);

// after doing setContentView, assuming you have defined a listview in your layout file
this.mContactsListView= (ListView) this.findViewById(R.id.contactsListView);
// You may want to create a custom adapter, which I wrote below for showing you example
this.mContactsListView.setAdapter(this.mContactsListAdapter);

for (/* each contact */) {

    Contact contact = new Contact();
    contact.name = contactName;
    contact.number = contactNumber;

    this.mContactsListAdapter.add(contact);
}

// In order to refresh your list and make data appear
this.mContactsListAdapter.notifyDataSetChanged();

当然，在我的示例中，您需要一个包含联系人数据的模型对象：

public class Contact  {

public String name;
public String number;

}

这可能是您使用上面的Contact类的自定义适配器：

public class ListContactItemAdapter extends ArrayAdapter<Contact> {

private int mLineLayout;
private LayoutInflater mInflater;

public ListContactItemAdapter(Context pContext, int pLineLayout) {
    super(pContext, pLineLayout);

    this.mLineLayout = pLineLayout;
    this.mInflater = (LayoutInflater) pContext.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
}

static class ViewHolder {

    TextView contactName;
    TextView contactNumber;
}

@Override
public View getView(int pPosition, View pView, ViewGroup pParent) {

    ViewHolder holder;
    if (pView == null) {

        pView = this.mInflater.inflate(this.mLineLayout, null);

        holder = new ViewHolder();
        holder.contactName = (TextView) pView.findViewById(R.id.contactName);
        holder.contactNumber = (TextView) pView.findViewById(R.id.contactNumber);

        pView.setTag(holder);

    } else {
        holder = (ViewHolder) pView.getTag();
    }

    Contact contact = getItem(pPosition);
    if (contact != null) {

        holder.contactName.setText(contact.name);
        holder.contactNumber.setText(contact.number);
    }

    return pView;
}

}

对于该示例，您需要一个布局来定义列表视图的行。这可以是contact_row.xml示例：

<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent" >

<TextView
    android:id="@+id/contactName"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:paddingLeft="6dp"
    android:text="Contact name"
    android:textAppearance="?android:attr/textAppearanceMedium" />

<TextView
    android:id="@+id/contactNumber"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:layout_below="@+id/contactName"
    android:paddingLeft="6dp"
    android:text="number"
    android:textAppearance="?android:attr/textAppearanceSmall" />


</RelativeLayout>

我没试过，但这应该有效。无论如何，我希望它能让你理解listviews基本上是如何工作的。

Answer 2

这是一种适应你已有的方法。我在改变之前添加了评论，以便解释：

public class nominateContactsActivity extends Activity {
    // Add a list to keep all the "name: number" strings
    private List<String> mNameNumber = new ArrayList<String>();

    public void onCreate(Bundle savedInstanceState){
        super.onCreate(savedInstanceState);
        setContentView(R.layout.nominatecontactslayout);
        Cursor c = getContentResolver().query(ContactsContract.Contacts.CONTENT_URI, null, null, null, null);
        String contactName, contactTelNumber = "";
        String contactID;

        // You only need to find these indices once
        int idIndex = c.getColumnIndex(ContactsContract.Contacts._ID);
        int hasNumberIndex = c.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER);
        int nameIndex = c.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME);


        // This is simpler than calling getCount() every iteration
        while(c.moveToNext()) {
            contactName = c.getString(nameIndex);
            contactID = c.getString(idIndex);

            // If this is an integer ask for an integer
            if (c.getInt(hasNumberIndex)) > 0) {
                Cursor pCur = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?", new String[] { contactID },null);
                while (pCur.moveToNext()) {
                    contactTelNumber = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));

                    // Store the "name: number" string in our list
                    mNameNumber.add(contactName + ": " + contactTelNumber);
                } 
            }
        }

        // Find the ListView, create the adapter, and bind them
        ListView listView = (ListView) findViewById(R.id.listView);
        ArrayAdapter<String> adapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, mNameNumber);
        listView.setAdapter(adapter);
    }
}

Android联系人 - 检索到的Android联系人，如何将它们放入简单的ListView中？

2 个答案: