嘿,我正在使用python脚本来测试网络商务网站上的功能。我把这个脚本放在pythonanywhere网站上,有时连续工作7天没有问题,但有几天,比如这个,当我收到这个错误时:
Logged in with test_cart
Open http://[***]/electronics/page/1
Search ... iphone
[****************]
File "/home/.../cart-pickup.py", line 58, in alo
site = opener.open(url)
File "/usr/local/lib/python2.7/urllib2.py", line 400, in open
response = self._open(req, data)
File "/usr/local/lib/python2.7/urllib2.py", line 418, in _open
'_open', req)
File "/usr/local/lib/python2.7/urllib2.py", line 378, in _call_chain
result = func(*args)
File "/usr/local/lib/python2.7/urllib2.py", line 1207, in http_open
return self.do_open(httplib.HTTPConnection, req)
File "/usr/local/lib/python2.7/urllib2.py", line 1180, in do_open
r = h.getresponse(buffering=True)
File "/usr/local/lib/python2.7/httplib.py", line 1030, in getresponse
response.begin()
File "/usr/local/lib/python2.7/httplib.py", line 407, in begin
version, status, reason = self._read_status()
File "/usr/local/lib/python2.7/httplib.py", line 371, in _read_status
raise BadStatusLine(line)
httplib.BadStatusLine: ''
>>>
任何想法可能是什么? 提前致谢
答案 0 :(得分:3)
您可以使用try..except
try:
site = opener.open(url) # line 58 in cart-pickup.py
except IOError:
print "Error: Site not loading or it isnt UP. Retrying..."
# return site # This will cause a NameError if site is not defined.
return url # Perhaps you meant this?
except httplib.BadStatusLine:
# log opening `url` did not succeed, or
# queue it to be tried again, etc.
pass