Question

我不擅长编程，也没有经验，这适用于教师辅助程度微不足道的课程。

标题是我得到的错误。这是功能：

void CapFormat (string Names, int NameCount)
 {
   int Comma;
   int c;
   int d;

    string::size_type len;

   for(c = 0; c < NameCount; c ++)
   {
     len = static_cast<unsigned> (Names[c].size);  //error starts here
     for(d = len; d > 0; d --)
     {
       tolower((Names[c].at(d)));  //supposed to lower cases every letter
     }
     touppper(Names[c].at(0));  //supposed to upper case first letter
     Comma = Names[c].find(",");  //supposed to find a comma between last and first names
     Comma = Comma + 1;
     toupper(Names[c].at(Comma));  //Error here as well.  supposed to then upper case letter after the comma.
   }
 }

以下是错误的扩展版本：

In function âvoid CapFormat(std::string, int)â:
error: request for member âsizeâ in âNames.std::basic_string<_CharT, _Traits, _Alloc>::operator[] [with _CharT = char, _Traits = std::char_traits<char>, _Alloc = std::allocator<char>](((long unsigned int)c))â, which is of non-class type âcharâ
error: request for member âatâ in âNames.std::basic_string<_CharT, _Traits, _Alloc>::operator[] [with _CharT = char, _Traits = std::char_traits<char>, _Alloc = std::allocator<char>](((long unsigned int)c))â, which is of non-class type âcharâ
error: request for member âatâ in âNames.std::basic_string<_CharT, _Traits, _Alloc>::operator[] [with _CharT = char, _Traits = error: âtouppperâ was not declared in this scope
error: request for member âfindâ in âNames.std::basic_string<_CharT, _Traits, _Alloc>::operator[] [with _CharT = char, _Traits = std::char_traits<char>, _Alloc = std::allocator<char>](((long unsigned int)c))â, which is of non-class type âcharâ
error: request for member âatâ in âNames.std::basic_string<_CharT, _Traits, _Alloc>::operator[] [with _CharT = char, _Traits = std::char_traits<char>, _Alloc = std::allocator<char>](((long unsigned int)c))â, which is of non-class type âcharâ

包括Cstring，cctype和string。我直接从我的书中复制了语法，一切都应该按顺序排列，但错误仍然存在。

非常感谢协助。

Answer 1

首先，在代码中使用Names参数的方式表明它应该是一个数组。但是你将它声明为单个对象。因此错误。

该参数显然应该声明为

void CapFormat (string Names[], int NameCount)

或

void CapFormat (string *Names, int NameCount)

（这是相同的。）将此与您的书进行比较。这是你的错误或书中的错误。

其次，size行应该看起来像

len = static_cast<unsigned>(Names[c].size());

（注意额外的()）。那里static_cast至unsigned完全没有必要。只是做

len = Names[c].size();

这是static_cast你的想法吗？如果它在书中，那将是一本相当奇怪的书。

不合适的int变量与适当的string::size_type变量的不合逻辑混合使我怀疑这实际上来自于一本书。

错误：请求成员大小...是非类型char

1 个答案: