UnicodeDecodeError:'ascii'编解码器无法解码位置304中0xc3中的字节:序数不在范围内(128)

时间:2012-08-10 22:08:47

标签: python macos syntax-error python-unicode

我刚刚离开了PC(使用Python 2.7)并且有一个我刚刚完成的脚本(在下面转载)。它在工作中运行良好,我只是想添加一两件事。但我回到家并使用我的Mac版Python(3.2.2),我收到以下错误:

Traceback (most recent call last):
  File "/Users/Downloads/sda/alias.py", line 25, in <module>
    for row_2 in in_csv:
  File "/Library/Frameworks/Python.framework/Versions/3.2/lib/python3.2/encodings/ascii.py", line 26, in decode
    return codecs.ascii_decode(input, self.errors)[0]
UnicodeDecodeError: 'ascii' codec can't decode byte 0xc3 in position 304: ordinal not in range(128)

我的代码在这里:

import csv
inname = "Fund_Aliases.csv"
outname = "output.csv"

def first_word(value):
    return value.split(" ", 1)[0]

with open(inname, "r") as infile:
    with open(outname, "w") as out file:
      in_csv = csv.reader(infile)
      out_csv = csv.writer(outfile)

     column_names = next(in_csv)
     out_csv.writerow(column_names)

      id_index = column_names.index("id")
      name_index = column_names.index("name")

      try:
          row_1 = next(in_csv)
          written_row = False

          for row_2 in in_csv:
            if first_word(row_1[name_index]) == first_word(row_2[name_index]) and row_1[id_index] != row_2[id_index]:
                if not written_row:
                    out_csv.writerow(row_1)

                out_csv.writerow(row_2)
                written_row = True
            else:
                written_row = False

            row_1 = row_2
      except StopIteration:
        # No data rows!
        pass

1 个答案:

答案 0 :(得分:5)

看起来Fund_Aliases.csv不是ascii文件。

根据Python3 docs

  

由于open()用于打开CSV文件进行读取,因此该文件将由   默认使用系统默认编码解码为unicode(请参阅   是locale.getpreferredencoding())。使用不同的文件解码文件   编码,使用open的编码参数:

with open('some.csv', newline='', encoding='utf-8') as f:
    reader = csv.reader(f)

因此请尝试指定encoding参数。