我正在尝试创建一个以字节数组作为源的图像对象。我究竟做错了什么?
当我尝试使用字节数组作为源数据初始化图像对象时,抛出异常。我的代码中显示了异常,如下所示。
public class MyClass
{
publuc System.Windows.Media.Imaging.BitmapImage InstanceImage { get; set; }
public void GetImage()
{
// Retrieves a list of custom "Item" objects that contain byte arrays.
// ScvClnt is our service client. The PollQueue method is designed to return information to us.
lstQueue = SvcClnt.PollQueue(1);
// This condition always evaluates as True, since we requested exactly 1 "Item" from the service client.
if (lstQueue.Count == 1)
{
// lstQueue[0].InstanceImage is a byte array containing the data from an image file.
// I have confirmed that it is a valid TIFF image file, by writing it to disk and opening it in MSPaint.
if (lstQueue[0].InstanceImage != null)
{
// This condition is also True, since the image is just under 3KB.
if (lstQueue[0].InstanceImage.Length > 0)
{
this.InstanceImage = new System.Windows.Media.Imaging.BitmapImage();
this.InstanceImage.BeginInit();
this.InstanceImage.StreamSource = new System.IO.MemoryStream(lstQueue[0].InstanceImage);
InstanceImage.EndInit();
// The call to EndInit throws a NullReferenceException.
// {"Object reference not set to an instance of an object."}
// I have confirmed that this.InstanceImage and this.InstanceImage.StreamSource are not null at this point.
// They are successfully assigned in the lines of code above.
} else InstanceImage = null;
} else InstanceImage = null;
} else InstanceImage = null;
}
}
我不知道地球上可能出现什么问题 任何建议都将不胜感激。
答案 0 :(得分:3)
乍一看,我不确定我是否正在按照你的课程进行操作,但为了解决原来的问题,请试一试:
public static Image ConvertByteArrayToImage(byte[] byteArrayIn)
{
MemoryStream ms = new MemoryStream(byteArrayIn);
Image returnImage = Image.FromStream(ms);
return returnImage;
}
答案 1 :(得分:2)
This MSDN forum post使用此示例作为解决方案。
using (MemoryStream stream = new MemoryStream(abyteArray0))
{
image.Source = BitmapFrame.Create(stream, BitmapCreateOptions.None, BitmapCacheOption.OnLoad);
}
//The field image should be of type System.Windows.Controls.Image.
我使用了BitmapFrame.Create方法,该方法仅将流作为参数,并且它像魅力一样工作。