TypeError：__ init __（）只需1个参数（给定3个）pyXML

Question

我最近开始学习如何使用python来解析xml文件。 我从http://pyxml.sourceforge.net/topics/howto/node12.html

获取了教程

当我运行以下代码时，我收到错误：

Traceback (most recent call last):
  File "C:\Users\Name\Desktop\pythonxml\tutorials\pythonxml\pyxml sourceforge\5.1 Comic Colection\SearchForComic.py", line 30, in -toplevel-
    dh = FindIssue('sandman', '62')
TypeError: __init__() takes exactly 1 argument (3 given)

码

from xml.sax import saxutils

class FindIssue(saxutils.DefaultHandler):
    def __init___(self, title, number):
        self.search_title, self.search_number = title, number

def startElement(self, name, attrs):
    #if it's not a comic element, ignore it
    if name!= 'comic': return

        # look for the title and number sttributes (see text)
        title = attrs.get('title', None)
        number = attrs.get('number', None)
        if (title == self.search_title and
            number == self.search_number):
                print title, '#' +str (number), 'found'

from xml.sax import make_parser
from xml.sax.handler import feature_namespaces

if __name__ == '__main__':
        #Create a parser
        parser = make_parser()

    #tell the parser that we are not interested in XML namespaces
        parser.setFeature(feature_namespaces, 0)

    #create the handler
    dh = FindIssue('sandman', '62')

    #tell the parse to use our handler
    parser.setContentHandler(dh)

    #parse the input
    parser.parse('collection.xml')

同样在最后一行，我将文件传递给当前工作目录，这是解决文件的正确方法吗？

Answer 1

你__init__的名字太多了_。构造函数的声明应该是：

def __init__(self, title, number):

不

def __init___(self, title, number):

Answer 2

你有一个拼写错误 - 这里有3个下划线：

def __init___(self, title, number):

应该是：

def __init__(self, title, number):

因为它与名称__init__不完全匹配，所以Python只知道默认构造函数def __init__(self)。