Question

如果选择陈述中没有行（选择前1 ...）

，则此语句会出错

update tHomePageWorking 
set nColumn = 2, 
    nPosition = ((select top 1 nPosition 
                  from tHomePageWorking 
                  where nColumn = 2 
                  order by nPosition desc) + 1
                 ) 
where nPosition = 1 and nColumn = 1

有没有办法测试此语句的计数，如果没有找到记录，则默认为1？

select top 1 nPosition 
from tHomePageWorking 
where nColumn = 2 
order by nPosition desc

Answer 1

我认为COALESCE功能会解决您的问题。它将返回第一个非null参数：

update tHomePageWorking 
set nColumn = 2, 
    nPosition = COALESCE (
                 ((select top 1 nPosition 
                  from tHomePageWorking 
                  where nColumn = 2 
                  order by nPosition desc) + 1
                 ) 
                 ,1)
where nPosition = 1 and nColumn = 1

Answer 2

一种方法是

declare @nposition int
set @nposition=(select top 1 nPosition 
                      from tHomePageWorking 
                      where nColumn = 2 
                      order by nPosition desc)
  update tHomePageWorking 
    set nColumn = 2, 
        nPosition = (coalesce(@nposition,0) + 1) 
    where nPosition = 1 and nColumn = 1

Answer 3

declare @pos int;
select @pos=(select top 1 nPosition 
                  from tHomePageWorking 
                  where nColumn = 2 
                  order by nPosition desc)
select @pos=ISNULL(@pos,0)+1;

update tHomePageWorking 
set nColumn = 2, 
    nPosition = @pos 
where nPosition = 1 and nColumn = 1

SQL Server：if ... else基于行计数

3 个答案: