我想通过电子邮件使用c#ASP.net发送文件(也许还有更多文件,但目前我担心发送至少一个文件)
目前,如果您想发送电子邮件,我确实有一种方法可行。
public string EnviarMensaje(int intIdVendedor, string strCorreoPara, string strCorreosAdicionales, string strTema, string strMensaje, string strRuta)
{
string strResultado="";
DataTable dt = ConexionBD.GetInstanciaConexionBD().GetVendedorEspecifico(intIdVendedor);
string strCuerpo = strMensaje + "\n\n\n\nMensaje Enviado Por:\n" + dt.Rows[0]["Vendedor"] + "\n" + dt.Rows[0]["Email"] + "\n" + dt.Rows[0]["Telefono"];
string[] strListaCorreos = strCorreosAdicionales.Split(new Char[] {' ', ','}, StringSplitOptions.RemoveEmptyEntries);
try
{
MailMessage mail = new MailMessage();
SmtpClient SmtpServer = new SmtpClient("smtpout.secureserver.net");
mail.Subject = strTema;
mail.Body = strCuerpo;
mail.From = new MailAddress(strCorreoDe);
mail.To.Add(strCorreoPara);
foreach (string c in strListaCorreos)
{
mail.To.Add(c);
}
if (strRuta != "")
{
Attachment attachment;
attachment = new Attachment(strRuta);
mail.Attachments.Add(attachment);
}
SmtpServer.Port = 80;
SmtpServer.Credentials = new System.Net.NetworkCredential(strCorreoDe, strContrasena);
SmtpServer.EnableSsl = false;
SmtpServer.Send(mail);
strResultado = "Exito";
}
catch (Exception ex)
{
strResultado = ex.ToString();
}
return strResultado;
}
在aspx中我有
<asp:FileUpload ID="fileUploadArchivos" runat="server" />
<asp:ImageButton ID="imgBtnEnviar" runat="server" Height="60px" Width="60px" ImageUrl="~/img/iconos/email.png" CausesValidation = "True" ValidationGroup="vgpCorreo" onclick="imgBtnEnviar_Click" />
和我有的cs
EnviarEmail objEmail = new EnviarEmail();
protected void imgBtnEnviar_Click(object sender, ImageClickEventArgs e)
{
if (fileUploadArchivos.HasFile)
{
strArchivo = Path.GetTempFileName();\\RIGHT NOW I LEFT IT THIS WAY, BUT I NOW THAT HERE IS THE PROBLEM, I DON'T KNOW WHTAT CAN I DO HERE
}
string strResultado = objEmail.EnviarMensaje((int)Session["IdVendedor"], lblCorreoPara.Text, tbxCorreoPara.Text, tbxTema.Text, tbxMensaje.Text, strArchivo);
}
但是,问题出在FileUpload中。 我尝试了很多方法,比如Server.MapPath,Path.GetFileName,GetDirectoryName,GetFullPath,GetPathRoot ...而且我总是得到什么,只有文件名或完全不同的路径(我猜是服务器类路径) ..
我目前只想获得一个像C:\ Test.txt这样简单的文件路径... 我想如果我能从FileUpload中获取那个确切的字符串,我就能发送它......但是,我无法弄清楚如何让它工作。
希望你能帮助我 感谢答案 0 :(得分:1)
如果您需要保存在服务器上的文件的本地副本,您可以这样做
fuFileUpload.SaveAs(MapPath(filepath));
然后你的strRuta可以使用你刚刚保存的文件
strRuta = Server.MapPath(filepath);
准备好传入新的附件对象。
答案 1 :(得分:0)
您无需将文件保存在所有到磁盘,如果您只想将其添加为附件,则无需将其添加。
FileUpload
的{{3}}属性为Stream
- FileContent
类的某些构造函数将流作为参数。
解决方案是将此流传递给您的方法并直接使用它。
在代码背后:
string strResultado = objEmail.EnviarMensaje((int)Session["IdVendedor"],
lblCorreoPara.Text,
tbxCorreoPara.Text,
tbxTema.Text,
tbxMensaje.Text,
fileUploadArchivos.FileContent);
在你班上:
public string EnviarMensaje(int intIdVendedor,
string strCorreoPara,
string strCorreosAdicionales,
string strTema,
string strMensaje,
Stream attachmentData)
{
...
var attachment = new Attachment(attachmentData, "nameOfAttachment");
...
}
答案 2 :(得分:0)
您可以尝试使用流而不是简单文本:
public string EnviarMensaje(int intIdVendedor, string strCorreoPara, string strCorreosAdicionales, string strTema, string strMensaje, string strRuta)
{
string strResultado="";
DataTable dt = ConexionBD.GetInstanciaConexionBD().GetVendedorEspecifico(intIdVendedor);
string strCuerpo = strMensaje + "\n\n\n\nMensaje Enviado Por:\n" + dt.Rows[0]["Vendedor"] + "\n" + dt.Rows[0]["Email"] + "\n" + dt.Rows[0]["Telefono"];
string[] strListaCorreos = strCorreosAdicionales.Split(new Char[] {' ', ','}, StringSplitOptions.RemoveEmptyEntries);
try
{
MailMessage mail = new MailMessage();
SmtpClient SmtpServer = new SmtpClient("smtpout.secureserver.net");
mail.Subject = strTema;
mail.Body = strCuerpo;
mail.From = new MailAddress(strCorreoDe);
mail.To.Add(strCorreoPara);
foreach (string c in strListaCorreos)
{
mail.To.Add(c);
}
bool hasAttachment = !string.IsNullOrWhitespace(strRuta);
System.IO.FileStream stream = null;
Attachment attachment = null;
if (hasAttachment)
{
// Create a file stream.
stream = new FileStream(strRuta, FileMode.Open, FileAccess.Read);
// Define content type.
ContentType contentType = new ContentType();
contentType.MediaType = MediaTypeNames.Text.Plain; // or whatever your attachment is
// Create the attachment and add it.
attachment = new Attachment(stream, contentType);
mail.Attachments.Add(attachment);
}
SmtpServer.Port = 80;
SmtpServer.Credentials = new System.Net.NetworkCredential(strCorreoDe, strContrasena);
SmtpServer.EnableSsl = false;
SmtpServer.Send(mail);
strResultado = "Exito";
// Don't forget to release the resources if the attachment has been added
if (hasAttachment)
{
data.Dispose();
stream.Close();
stream.Dispose();
}
}
catch (Exception ex)
{
strResultado = ex.ToString();
}
return strResultado;
}