Question

我有三种模式：帐户，会员和儿童。

Member belongs to Account
Child belongs to Member

会员拥有account_id属性儿童没有account_id 属性

所以我可以这样做......

Member.where(:account_id => current_user.account.id)

c = Child.last
c.member.account_id

在索引操作中，我想列出属于特定帐户的所有子项。我不想在account_id表中添加额外的children列。

当然，我不能这样做......

Child Model
def account_id
  self.member.account_id
end

Children Controller
Child.where(:account_id => current_user.account.id)

有没有办法列出属于特定帐户的所有子项而无需添加account_id属性？

顺便说一句，我在现有的查询中有这个......

@children = Child.search(params[:search]).order(sort_column + ' ' + sort_direction).page(params[:page]).per(10)

Answer 1

从Child类开始，可以这样做：

Child.includes(:member).where(:'members.account_id' => current_user.account.id)

这可用于修改现有查询。

Answer 2

class Account < ActiveRecord::Base
  has_many :members
  #This is the line you were looking for
  has_many :children, :through => :members
end

class Member < ActiveRecord::Base
  belongs_to :account
  has_many :children, :class_name => "Child"
end

class Child < ActiveRecord::Base
  belongs_to :member
end

现在假设您有一个帐户实例，您可以通过以下方式访问其所有子项：

account.children

轨。虚拟属性（来自父模型）查询

2 个答案: