我只是想在我的列表中只获取第一个<song>
;我正在使用的代码工作正常,但只在我的列表中获取类似标记的最后条目(<song>
)。这是我的XML:
<songs id="stationid">
<song>
<title>
<![CDATA[ Last Breath ]]>
</title>
<artist>
<![CDATA[ Xela ]]>
</artist>
<album>
<![CDATA[ For Frosty Mornings And Summer Nights ]]>
</album>
<albumart>
<![CDATA[ ]]>
</albumart>
<date>1344536317</date>
</song>
<song>
<title>
<![CDATA[ Turn On Switch Off (Starring Valerie Trebeljahr) ]]>
</title>
<artist>
<![CDATA[ Static ]]>
</artist>
<album>
<![CDATA[ Flavour Has No Name ]]>
</album>
<albumart>
<![CDATA[ ]]>
</albumart>
<date>1344536000</date>
</song>
<song>
<title>
<![CDATA[ Aim Low ]]>
</title>
<artist>
<![CDATA[ Sheik & Beige ]]>
</artist>
<album>
<![CDATA[ Sty Wars - A Collection of Por ]]>
</album>
<albumart>
<![CDATA[ ]]>
</albumart>
<date>1344531485</date>
</song>
</songs>
和我的代码:(我想只检索第一个列表项,因为当歌曲发生变化时,Feed会更新,我希望当前播放的歌曲始终位于列表的顶部)
package com.example.networking;
import android.app.Activity;
import android.os.Bundle;
import java.io.IOException;
import java.io.InputStream;
import java.net.HttpURLConnection;
import java.net.URL;
import java.net.URLConnection;
import android.util.Log;
import android.widget.ImageView;
import android.widget.Toast;
import android.graphics.Bitmap;
import android.graphics.BitmapFactory;
import android.os.AsyncTask;
import java.io.InputStreamReader;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
public class NetworkingActivity extends Activity {
private InputStream OpenHttpConnection(String urlString)
throws IOException
{
InputStream in = null;
int response = -1;
URL url = new URL(urlString);
URLConnection conn = url.openConnection();
if (!(conn instanceof HttpURLConnection))
throw new IOException("Not an HTTP connection");
try{
HttpURLConnection httpConn = (HttpURLConnection) conn;
httpConn.setAllowUserInteraction(false);
httpConn.setInstanceFollowRedirects(true);
httpConn.setRequestMethod("GET");
httpConn.connect();
response = httpConn.getResponseCode();
if (response == HttpURLConnection.HTTP_OK) {
in = httpConn.getInputStream();
}
}
catch (Exception ex)
{
Log.d("Networking", ex.getLocalizedMessage());
throw new IOException("Error connecting");
}
return in;
}
private String WordDefinition(String word) {
InputStream in = null;
String strDefinition = "";
try {
in = OpenHttpConnection(
"http://api.somafm.com/songs/groovesalad.xml");
Document doc = null;
DocumentBuilderFactory dbf =
DocumentBuilderFactory.newInstance();
DocumentBuilder db;
try {
db = dbf.newDocumentBuilder();
doc = db.parse(in);
} catch (ParserConfigurationException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
doc.getDocumentElement().normalize();
//---retrieve all the <song> elements---
NodeList definitionElements =
doc.getElementsByTagName("song");
//---iterate through each <song> elements---
for (int i = 0; i < definitionElements.getLength(); i++) {
Node itemNode = definitionElements.item(i);
if (itemNode.getNodeType() == Node.ELEMENT_NODE)
{
//---convert the song node into an Element---
Element definitionElement = (Element) itemNode;
//---get all the <artist> elements under
// the <song> element---
NodeList wordDefinitionElements =
(definitionElement).getElementsByTagName(
"artist");
strDefinition = "";
//---iterate through each <artist> elements---
for (int j = 0; j < wordDefinitionElements.getLength(); j++) {
//---convert an <artist> node into an Element---
Element wordDefinitionElement =
(Element) wordDefinitionElements.item(j);
//---get all the child nodes under the
// <artist> element---
NodeList textNodes =
((Node) wordDefinitionElement).getChildNodes();
strDefinition +=
((Node) textNodes.item(0)).getNodeValue() + ". \n";
}
}
}
} catch (IOException e1) {
Log.d("NetworkingActivity", e1.getLocalizedMessage());
}
//---return the definitions of the word---
return strDefinition;
}
private class AccessWebServiceTask extends AsyncTask<String, Void, String> {
protected String doInBackground(String... urls) {
return WordDefinition(urls[0]);
}
protected void onPostExecute(String result) {
Toast.makeText(getBaseContext(), result, Toast.LENGTH_LONG).show();
}
}
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
//---access a Web Service using GET---
new AccessWebServiceTask().execute("apple");
}
}
感谢有人可以帮助我!
答案 0 :(得分:0)
当你第一次点击内部循环中的最后一个语句时,你应该在WordDefinition中打破外部for循环。您可以这样做,例如,通过设置标志并在for
中对其进行测试boolean flag = false;
for (int i = 0; i < definitionElements.getLength && !flag; i++) {
...
strDefinition +=
((Node) textNodes.item(0)).getNodeValue() + ". \n";
flag = true;
break;
我更喜欢使用XPath,如下所示:
private String WordDefinition(String word) {
InputStream in = null;
String strDefinition = "";
XPathFactory xPathFactory = XPathFactory.newInstance();
XPath xPath = xPathFactory.newXPath();
try {
in = OpenHttpConnection(
"http://api.somafm.com/songs/groovesalad.xml");
XPathExpression xPathExpression = xPath.compile("/songs/song[1]/artist");
Node node = (Node) xPathExpression.evaluate(new InputSource(in), XPathConstants.NODE);
strDefinition = node.getTextContent();
}
catch (IOException e1) {
Log.d("NetworkingActivity", e1.getLocalizedMessage());
}
catch (XPathExpressionException e1) {
Log.d("NetworkingActivity", e1.getLocalizedMessage());
}
// ---return the definitions of the word---
return strDefinition;
}