在Python 2.7中编写一个文件而不被Windows阻止?

时间:2012-08-09 16:16:52

标签: python windows-7 permissions

我正在编写一个简单的模糊器,用于基于Charlie Miller代码的Windows应用程序,这些代码来自于一群猴子的谈话。但是我一直收到错误

  Traceback (most recent call last):
  File "D:/Python27/fuzzer.py", line 29, in <module>
    process=subprocess.Popen([app_choice,fuzz_output])
  File "D:\Python27\lib\subprocess.py", line 679, in __init__
    errread, errwrite)
  File "D:\Python27\lib\subprocess.py", line 896, in _execute_child
   startupinfo)
WindowsError: [Error 5] Access is denied

有谁知道如何绕过这个?我真的很难过,因为我不太熟悉Windows 7权限或Python 2.7。完整代码

#List of file names (all located in the python folder)
fuzz_files=[ "slides_algo-guiding.pdf", "slides_algo-intro-annotated-   final.pdf","slides_algo-merge1.pdf"]
apps=["C:\Program Files (x86)\Adobe\Reader 9.0\Reader"
  ]
#Creates an output file in the Python folder
fuzz_output="fuzz.pdf"
FuzzFactor=50
num_tests=1000
import math
import string
import random
import subprocess
import time

for i in range(num_tests):
    file_choice=random.choice(fuzz_files)
    app_choice=random.choice(apps)
    buf=bytearray(open(file_choice,'rb').read())
    #Charlie Miller code

    numwrites=random.randrange(math.ceil((float(len(buf))/FuzzFactor)))+1
    for j in range(numwrites):
        rbyte=random.randrange(256)
        rn=random.randrange(len(buf))
        buf[rn]="%c"%(rbyte)
     #End Charlie miller code

     #Write code
     open(fuzz_output,'wb').write(buf)
     process=subprocess.Popen([app_choice,fuzz_output])

     time.sleep(1)
     crashed=process.poll()
    if not crashed:
       process.terminate()

1 个答案:

答案 0 :(得分:1)

我认为C:\Program Files (x86)\Adobe\Reader 9.0\Reader文件夹的路径,而不是可执行文件。因此,尝试使用Popen运行它是没有意义的。

此外,在编写Windows路径r"C:\Program Files (x86)\Adobe\Reader 9.0\Reader\AcroRd32.exe"或使用斜杠而不是"C:/Program Files (x86)/Adobe/Reader 9.0/Reader/AcroRd32.exe"时,您应该使用原始字符串。你很幸运,路径中没有任何有效的转义序列。