MySQL:'EXPLAIN'显示类似查询的不同解释

时间:2012-08-09 12:00:05

标签: mysql sql key explain

我在数据库中有一个表'posts',它在user_id(Key:MUL)上有非唯一索引。

mysql> show columns from posts;
+---------+--------------+------+-----+-------------------+----------------+
| Field   | Type         | Null | Key | Default           | Extra          |
+---------+--------------+------+-----+-------------------+----------------+
| id      | int(11)      | NO   | PRI | NULL              | auto_increment |
| user_id | int(11)      | YES  | MUL | NULL              |                |
| post    | varchar(140) | NO   |     | NULL              |                |
+---------+--------------+------+-----+-------------------+----------------+

对于此表,解释给出了预期解释,其中类型为“ REF

mysql> explain select * from posts where posts.user_id=1;
+----+-------------+-------+------+---------------+---------+---------+-------+------+-------------+
| id | select_type | table | type | possible_keys | key     | key_len | ref   | rows | Extra       |
+----+-------------+-------+------+---------------+---------+---------+-------+------+-------------+
|  1 | SIMPLE      | posts | ref  | user_id       | user_id | 5       | const |   74 | Using where |
+----+-------------+-------+------+---------------+---------+---------+-------+------+-------------+

我有第二个表'追随者',其中'user_id'和'追随者'是非唯一索引的一部分

mysql> show columns from followers;
+---------------+-----------+------+-----+---------------------+----------------+
| Field         | Type      | Null | Key | Default             | Extra          |
+---------------+-----------+------+-----+---------------------+----------------+
| id            | int(11)   | NO   | PRI | NULL                | auto_increment |
| user_id       | int(11)   | YES  | MUL | NULL                |                |
| follower      | int(11)   | YES  | MUL | NULL                |                |
+---------------+-----------+------+-----+---------------------+----------------+

但是在此表中,输入为“ ALL ”。我预计它与前一个表中的'user_id'类似' REF ',这个'user_id'也有非唯一索引。对此有任何解释吗?

mysql> explain select * from followers where followers.user_id=1;
+----+-------------+-----------+------+---------------+------+---------+------+------+-------------+
| id | select_type | table     | type | possible_keys | key  | key_len | ref  | rows | Extra       |
+----+-------------+-----------+------+---------------+------+---------+------+------+-------------+
|  1 | SIMPLE      | followers | ALL  | user_id       | NULL | NULL    | NULL |    6 | Using where |
+----+-------------+-----------+------+---------------+------+---------+------+------+-------------+

1 个答案:

答案 0 :(得分:2)

我会把它作为答案发布,因为我很确定是这种情况。

我认为您会产生差异,因为在followers表中,您有来自user_idfollower字段的复合键,而不仅仅是user_id上的键。

因此,索引将用于在user_id子句中同时使用followerWHERE的查询。

user_id字段上添加单独的索引,您将得到相同的解释。