我有一个蒙面文本框,我希望它能够接受双值。对于小数点之前/之后可以适合的字符数量,不应该有任何排序限制。
我意识到还有其他方法可以做到这一点,比如重写键输入事件或使用数字向上但我只是问是否可以使用掩码。
我尝试了9999999999.99999999 - 但它给了我很多问题 - 例如:
1 2 3 4。 6 被接受作为输入(包括空格),我无法放弃。无论我想去哪里。
答案 0 :(得分:0)
这是一个简单的解决方案。不需要口罩。通常,遮罩并不能解决所有问题。我写了最初的解决方案。如果需要,可以将其与面罩组合。
Public Class Form1
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
AddHandlerTextBoxDouble(TextBox1)
End Sub
Public Sub AddHandlerTextBoxDouble(ByVal TextBoxMe As Object)
Dim TextBox As New TextBox
TextBox = CType(TextBoxMe, TextBox)
AddHandler TextBox.KeyPress, AddressOf TextBox_KeyPress
AddHandler TextBox.TextChanged, AddressOf TextBox_TextChanged
End Sub
Private Sub TextBox_KeyPress(ByVal sender As Object, ByVal e As System.Windows.Forms.KeyPressEventArgs)
ValidatingNumber(e, sender)
End Sub
Public Sub TextBox_TextChanged(ByVal sender As Object, ByVal e As System.EventArgs)
Dim TextBox As New TextBox
TextBox = CType(sender, TextBox)
If Not IsNumeric(TextBox.Text) And TextBox.Text <> "." Then
TextBox.Text = ""
End If
End Sub
Public Sub ValidatingNumber(ByVal e As Object, ByVal control As Object)
Try
If CType(control, TextBox).Text.IndexOf(".") > -1 And e.KeyChar = "." Then
e.KeyChar = ""
End If
If (Asc(e.KeyChar) < 58 And Asc(e.KeyChar) > 47) Or e.KeyChar = vbBack Or e.KeyChar = "." Then
e.KeyChar = e.KeyChar
Else
e.KeyChar = ""
Try
CType(e, System.Windows.Forms.KeyPressEventArgs).Handled = True
Catch ex As Exception
End Try
End If
Catch ex As Exception
MsgBox("ValidatingNumber")
End Try
End Sub
End Class