我正在尝试在我的BlackBerry应用程序中实现“等待屏幕”。用户单击“登录”时将显示该屏幕,并且在成功登录后该屏幕将消失。我在“登录”监听器中调用屏幕,之后我调用了一个从web服务器获取数据的方法。获取数据并显示新屏幕时,“等待屏幕”应消失。但是,在点击登录时,我得到Uncaught - RuntimeException
,然后显示新屏幕,并在其上方显示“等待屏幕”。有人可以帮我吗?
public class MessageScreen extends PopupScreen
{
private String message;
public MessageScreen (String message)
{
super( new HorizontalFieldManager(), Field.NON_FOCUSABLE);
this.message = message;
final BitmapField logo = new BitmapField(Bitmap.getBitmapResource( "cycle.gif"));
logo.setSpace( 5, 5 );
add(logo);
RichTextField rtf = new RichTextField(message, Field.FIELD_VCENTER | Field.NON_FOCUSABLE | Field.FIELD_HCENTER);
rtf.setEditable( false );
add(rtf);
}
}
我在“登录”点击事件 - 按钮监听器中调用它。
public void fieldChanged(Field field, int context)
{
// Push appropriate screen depending on which button was clicked
String uname = username.getText();
String pwd = passwd.getText();
if (uname.length() == 0 || pwd.length()==0) {
Dialog.alert("One of the textfield is empty!");
} else {
C0NNECTION_EXTENSION=checkInternetConnection();
if(C0NNECTION_EXTENSION==null)
{
Dialog.alert("Check internet connection and try again");
}
else
{
UiApplication.getUiApplication().invokeLater( new Runnable()
{
public void run ()
{
UiApplication.getUiApplication().pushScreen( new MessageScreen("Signing in...") );
}
} );
doLogin(uname, pwd);
}
}
}
private String doLogin(String user_id, String password)
{
String URL ="";
String METHOD_NAME = "ValidateCredentials";
String NAMESPACE = "http://tempuri.org/";
String SOAP_ACTION = NAMESPACE+METHOD_NAME;
SoapObject resultRequestSOAP = null;
HttpConnection httpConn = null;
HttpTransport httpt;
SoapPrimitive response = null;
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
request.addProperty("username", user_id);
request.addProperty("password", password);
System.out.println("The request is=======" + request.toString());
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet = true;
envelope.setOutputSoapObject(request);
httpt = new HttpTransport(URL+C0NNECTION_EXTENSION);
httpt.debug = true;
try
{
httpt.call(SOAP_ACTION, envelope);
response = (SoapPrimitive) envelope.getResponse();
String result = response.toString();
resultRequestSOAP = (SoapObject) envelope.bodyIn;
String[] listResult = split(result, sep);
strResult = listResult[0].toString();
strsessionFirstName = listResult[1].toString();
strsessionLastName = listResult[2].toString();
strsessionPictureUrl = MAINURL + listResult[3].substring(2);
strsessionStatusId = listResult[4].toString();
strsessionStatusMessage = listResult[5].toString();
strsessionLastUpdateTst = listResult[6].toString();
if(strResult.equals("credentialaccepted"))
{
if(checkBox1.getChecked() == true)
{
persistentHashtable.put("username", user_id);
persistentHashtable.put("password", password);
}
Bitmap bitmap = getLiveImage(strsessionPictureUrl, 140, 140);
StatusActivity nextScreen = new StatusActivity();
nextScreen.getUsername(user_id);
nextScreen.getPassword(password);
nextScreen.setPictureUrl(bitmap);
nextScreen.setImage(strsessionPictureUrl);
nextScreen.setFirstName(strsessionFirstName, strsessionLastName, strsessionLastUpdateTst, strsessionStatusMessage);
UiApplication.getUiApplication().pushScreen(nextScreen);
UiApplication.getUiApplication().invokeLater( new Runnable()
{
public void run ()
{
UiApplication.getUiApplication().pushScreen( UiApplication.getUiApplication().getActiveScreen() );
}
} );
}
if(strResult.equals("credentialdenied"))
{
Dialog.alert("Invalid login details.");
UiApplication.getUiApplication().pushScreen(new LoginTestScreen() );
}
} catch (IOException e) {
// TODO Auto-generated catch block
System.out.println("The exception is IO==" + e.getMessage());
} catch (XmlPullParserException e) {
// TODO Auto-generated catch block
System.out.println("The exception xml parser example==="
+ e.getMessage());
}
System.out.println( resultRequestSOAP);
//UiApplication.getUiApplication().pushScreen( UiApplication.getUiApplication().getActiveScreen() );
return response + "";
//UiApplication.getUiApplication().pushScreen(new InfoScreen());
//Open a new Screen
}
答案 0 :(得分:2)
到目前为止,我只看到一个问题 - 在UI线程中进行联网。请将您的所有网络操作放入另一个Thread.run()
。
您还可以通过以下方式获得更详细的错误说明: 1)导航到主屏幕 2)按住alt按钮并按下键盘上的LGLG 3)探索显示特定错误的事件日志
答案 1 :(得分:2)
与欧根说的一样,你应该在后台doLogin()
上运行Thread
:
final String uname = username.getText();
final String pwd = passwd.getText();
Thread backgroundWorker = new Thread(new Runnable() {
public void run() {
doLogin(uname, pwd);
}
});
backgroundWorker.start();
如果您这样做,则需要使用UiApplication.invokeLater()
(或其他类似技术)来显示您的屏幕(返回主/ UI线程)。您不能完全保留doLogin()
方法,因为它会调用更改UI。例如,您有几个直接使用pushScreen()
的调用,不应该从后台调用(直接)。
这不行(从后台开始):
UiApplication.getUiApplication().pushScreen(nextScreen);
但是,这是:
UiApplication.getUiApplication().invokeLater( new Runnable()
{
public void run ()
{
UiApplication.getUiApplication().pushScreen(nextScreen);
}
} );
但是,这个代码应该做什么呢? :
UiApplication.getUiApplication().pushScreen(nextScreen);
UiApplication.getUiApplication().invokeLater( new Runnable()
{
public void run ()
{
UiApplication.getUiApplication().pushScreen( UiApplication.getUiApplication().getActiveScreen() );
}
} );
这对我没有意义。你想用这些代码做什么?
答案 2 :(得分:1)
试试这个 -
public void fieldChanged(Field field, int context)
{
// Push appropriate screen depending on which button was clicked
String uname = username.getText();
String pwd = passwd.getText();
if (uname.length() == 0 || pwd.length()==0) {
Dialog.alert("One of the textfield is empty!");
} else {
C0NNECTION_EXTENSION=checkInternetConnection();
if(C0NNECTION_EXTENSION==null)
{
Dialog.alert("Check internet connection and try again");
}
else
{
Dialog busyDialog = new Dialog("Signing in...", null, null, 0, Bitmap.getPredefinedBitmap(Bitmap.HOURGLASS));
busyDialog.setEscapeEnabled(false);
synchronized (Application.getEventLock()) {
busyDialog.show();
}
doLogin(uname, pwd);
}
}
}