如何将字符串转换为十六进制字符串？

Question

如果我有一个字符串，如何在Objective-C中将值转换为十六进制？同样，我如何从十六进制字符串转换为字符串？

Answer 1

作为一项练习，如果它有所帮助，我写了一个程序来演示如何在纯C中实现这一点，这在Objective-C中是100％合法的。我使用stdio.h中的字符串格式化函数来进行实际转换。

请注意，这可以（应该？）为您的设置进行调整。它将创建一个字符串，当传入char-＆gt; hex（例如将'Z'转换为'5a'）时，传入字符串的长度是传递的字符串的两倍，而字符串的长度则是另一半。

我用这样的方式编写了这段代码，你可以简单地复制/粘贴然后编译/运行来玩它。这是我的示例输出：

我最喜欢在XCode中包含C的方法是创建一个.h文件，其函数声明与带有实现的.c文件分开。见评论：

#include <string.h>
#include <stdlib.h>
#include <stdio.h>

// Place these prototypes in a .h to #import from wherever you need 'em
// Do not import the .c file anywhere.
// Note: You must free() these char *s 
//
// allocates space for strlen(arg) * 2 and fills
// that space with chars corresponding to the hex
// representations of the arg string
char *makeHexStringFromCharString(const char*);
//
// allocates space for about 1/2 strlen(arg)
// and fills it with the char representation
char *makeCharStringFromHexString(const char*);


// this is just sample code
int main() {
    char source[256];
    printf("Enter a Char string to convert to Hex:");
    scanf("%s", source);
    char *output = makeHexStringFromCharString(source);
    printf("converted '%s' TO: %s\n\n", source, output);
    free(output);
    printf("Enter a Hex string to convert to Char:");
    scanf("%s", source);
    output = makeCharStringFromHexString(source);
    printf("converted '%s' TO: %s\n\n", source, output);
    free(output);
}


// Place these in a .c file (named same as .h above)
// and include it in your target's build settings
// (should happen by default if you create the file in Xcode)
char *makeHexStringFromCharString(const char*input) {
    char *output = malloc(sizeof(char) * strlen(input) * 2 + 1);
    int i, limit;
    for(i=0, limit = strlen(input); i<limit; i++) {
        sprintf(output + (i*2), "%x", input[i]);
    }
    output[strlen(input)*2] = '\0';
    return output;
}

char *makeCharStringFromHexString(const char*input) {
    char *output = malloc(sizeof(char) * (strlen(input) / 2) + 1);
    char sourceSnippet[3] = {[2]='\0'};
    int i, limit;
    for(i=0, limit = strlen(input); i<limit; i+=2) {
        sourceSnippet[0] = input[i];
        sourceSnippet[1] = input[i+1];
        sscanf(sourceSnippet, "%x", (int *) (output + (i/2)));
    }
    output[strlen(input)/2+1] = '\0';
    return output;
}