Question

我需要使用HtmlAgilityPack和C＃解析这个html代码。我可以得到 div class =“patent_bibdata”节点，但我不知道如何通过子节点循环。

在这个样本中有6个href，但我需要将它们分成两组;发明人，分类。我对最后两个不感兴趣。这个div中可以有任意数量的href。

正如您所看到的，在两组之前有一个文字说明了什么是hrefs。

代码段

HtmlWeb hw = new HtmlWeb();
HtmlDocument doc = m_hw.Load("http://www.google.com/patents/US3748943");
string xpath = "/html/body/table[@id='viewport_table']/tr/td[@id='viewport_td']/div[@class='vertical_module_list_row'][1]/div[@id='overview']/div[@id='overview_v']/table[@id='summarytable']/tr/td/div[@class='patent_bibdata']";
HtmlNode node = m_doc.DocumentNode.SelectSingleNode(xpath);

那你怎么做呢？

<div class="patent_bibdata">
    <b>Inventors</b>:&nbsp;
    <a href="http://www.google.com/search?tbo=p&amp;tbm=pts&amp;hl=en&amp;q=ininventor:%22Ronald+T.+Lashley%22">
    Ronald T. Lashley
    </a>, 
    <a href="http://www.google.com/search?tbo=p&amp;tbm=pts&amp;hl=en&amp;q=ininventor:%22Ronald+T.+Lashley%22">
    Ronald T. Lashley
    </a><br>
    <b>Current U.S. Classification</b>:&nbsp;
    <a href="http://www.google.com/url?id=3eF8AAAAEBAJ&amp;q=http://www.uspto.gov/web/patents/classification/uspc084/defs084.htm&amp;usg=AFQjCNEZRFtAyKTfNudgc-XVt2-VboD77Q#C084S31200P">84/312.00P</a>;
    <a href="http://www.google.com/url?id=3eF8AAAAEBAJ&amp;q=http://www.uspto.gov/web/patents/classification/uspc084/defs084.htm&amp;usg=AFQjCNEZRFtAyKTfNudgc-XVt2-VboD77Q#C084S31200R">84/312.00R</a><br>
    <br>
    <a href="http://www.google.com/url?id=3eF8AAAAEBAJ&q=http://patft.uspto.gov/netacgi/nph-Parser%3FSect2%3DPTO1%26Sect2%3DHITOFF%26p%3D1%26u%3D/netahtml/PTO/search-bool.html%26r%3D1%26f%3DG%26l%3D50%26d%3DPALL%26RefSrch%3Dyes%26Query%3DPN/3748943&usg=AFQjCNGKUic_9BaMHWdCZtCghtG5SYog-A">
    View patent at USPTO</a><br>
    <a href="http://www.google.com/url?id=3eF8AAAAEBAJ&q=http://assignments.uspto.gov/assignments/q%3Fdb%3Dpat%26pat%3D3748943&usg=AFQjCNGbD7fvsJjOib3GgdU1gCXKiVjQsw">
    Search USPTO Assignment Database
    </a><br>
</div>

想要结果 InventorGroup =

<a href="http://www.google.com/search?tbo=p&amp;tbm=pts&amp;hl=en&amp;q=ininventor:%22Ronald+T.+Lashley%22">
    Ronald T. Lashley
    </a>
    <a href="http://www.google.com/search?tbo=p&amp;tbm=pts&amp;hl=en&amp;q=ininventor:%22Ronald+T.+Lashley%22">
    Thomas R. Lashley
    </a>

ClassificationGroup

<a href="http://www.google.com/url?id=3eF8AAAAEBAJ&amp;q=http://www.uspto.gov/web/patents/classification/uspc084/defs084.htm&amp;usg=AFQjCNEZRFtAyKTfNudgc-XVt2-VboD77Q#C084S31200P">84/312.00P</a>;
    <a href="http://www.google.com/url?id=3eF8AAAAEBAJ&amp;q=http://www.uspto.gov/web/patents/classification/uspc084/defs084.htm&amp;usg=AFQjCNEZRFtAyKTfNudgc-XVt2-VboD77Q#C084S31200R">84/312.00R</a>

我正试图抓取的页面：http://www.google.com/patents/US3748943

// Anders

PS！我知道在这个页面中发明者的名字是相同的，但在大多数人中他们是不同的！

Answer 1

XPATH是你的朋友！像这样的东西会让你获得发明者的名字：

HtmlWeb w = new HtmlWeb();
HtmlDocument doc = w.Load("http://www.google.com/patents/US3748943");
foreach (HtmlNode node in doc.DocumentNode.SelectNodes("//div[@class='patent_bibdata']/br[1]/preceding-sibling::a"))
{
    Console.WriteLine(node.InnerHtml);
}

Answer 2

所以很明显我还不了解XPath。所以我提出了这个解决方案。也许不是最聪明的解决方案，但它确实有效！

// Anders

List<string> inventorList = new List<string>();
List<string> classificationList = new List<string>();

string xpath = "/html/body/table[@id='viewport_table']/tr/td[@id='viewport_td']/div[@class='vertical_module_list_row'][1]/div[@id='overview']/div[@id='overview_v']/table[@id='summarytable']/tr/td/div[@class='patent_bibdata']";
HtmlNode nodes = m_doc.DocumentNode.SelectSingleNode(xpath);
bool bInventors = false;
bool bClassification = false;
for (int i = 0; i < nodes.ChildNodes.Count; i++)
{
    HtmlNode node = nodes.ChildNodes[i];
    string txt = node.InnerText;
    if (txt.IndexOf("Inventor") > -1)
    {
        bClassification = false;
        bInventors = true;
    }
    if (txt.IndexOf("Classification") > -1)
    {
        bClassification = true;
        bInventors = false;
    }
    if (txt.IndexOf("USPTO") > -1)
    {
        bClassification = false;
        bInventors = false;
    }
    string name = node.Name;
    if (name.IndexOf("a") > -1)
    {
        if (bInventors)
        {
            string inventor = node.InnerText;
            inventorList.Add(inventor);
        }
        if (bClassification)
        {
            string classification = node.InnerText;
            classificationList.Add(classification);
        }
    }

循环通过HtmlAgilityPack创建的节点

2 个答案: