Question

我正在尝试使用PHP PDO语法。也许somone可以看看代码的和平。这似乎有点多的努力。

我抓住用户后置输入（ID）。知道我需要计算原因所有用户的BejagFlach值（它们的总和）和ID标识的用户的单值BejagFlach。我这样需要两个查询吗？还是有更短/更好的方式？

/* Fetch POST Data */
$User_Num = $_POST['User_Num'];

/* Build query for one User */
$dbSelect =  $objDb->prepare("SELECT BejagFlach,Name FROM Benutzer WHERE lfdNr = :User_Num");
$dbSelect -> setFetchMode(PDO::FETCH_ASSOC);  
$dbSelect->execute(array(':User_Num' => $User_Num));

/* Build query for all Users */
$dbSelect2 =  $objDb->prepare("SELECT BejagFlach FROM Benutzer");
$dbSelect2 -> setFetchMode(PDO::FETCH_ASSOC);  
$dbSelect2->execute();

/* Output + Calculate */    
while($row = $dbSelect->fetch()) {  
    $totalUser +=  $row['BejagFlach'];
    $who = utf8_encode($row['Name']);
}  

/* Output + Calculate */    
while($row = $dbSelect2->fetch()) {  
    $totalAll += $row['BejagFlach'];
}

亲切的问候，托尼

Answer 1

不，它似乎不太多？

我唯一要改变的是，如果您只是在匹配的记录数量之后，请使用rowCount

<?php
    $sel = $dbh->prepare('select * FROM fruit');
    $sel->execute();

    /* Return number of rows that were deleted */
    print("Return number of rows that were selected:\n");
    $count = $sel->rowCount();
    print("Seleted $count rows.\n");
?>

Answer 2

由于您至少需要第二个查询，我会这样做，因此您只需要对数据库进行1次请求：

$dbSelect =  $objDb->prepare("SELECT BejagFlach,lfdNr FROM Benutzer");
$dbSelect -> setFetchMode(PDO::FETCH_ASSOC);  
$dbSelect ->execute();
while($row = $dbSelect->fetch()) {  
    $totalAll +=  $row['BejagFlach'];
    if( $row['lfdNr'] == $UserNom) {
        $totalUser += $row['BejagFlach'];
        $who = utf8_encode($row['Name']);
    }
}

php pdo两个nealry相似的选择

2 个答案: