Question

public String passlink(String companyName, String mailName) {

    Session session = Hibernateutil.getSessionFactory().openSession();

    Transaction transaction = null;

    try {
        transaction = session.beginTransaction();

        String queryString="UPDATE account SET companyname = :companyName WHERE companyname like 'm' AND Email LIKE :mailName";
        Query query=session.createQuery(queryString);

        query.setParameter("companyName", companyName);
        query.setParameter("mailName", mailName);
        int result = query.executeUpdate();

        System.out.println("Rows affected: " + result);

            System.out.println("Successfully updated");
        transaction.commit();

    } catch (Exception e) {
        value = "FAIL";
                   e.printStackTrace();
        //System.out.println("Error--> " + e.getMessage());
    }
    return value;

}

我写更新查询

String queryString =“UPDATE account SET companyname =：companyName WHERE companyname like'm'AND Email LIKE：mailName”;

像这样，但它会出现以下错误。

java.lang.IndexOutOfBoundsException：Index：0，Size：0 at java.util.ArrayList.RangeCheck（Unknown Source） at java.util.ArrayList.get（Unknown Source）在org.hibernate.hql.ast.HqlSqlWalker.postProcessUpdate（HqlSqlWalker.java:390）在org.hibernate.hql.antlr.HqlSqlBaseWalker.statement（HqlSqlBaseWalker.java:164）在org.hibernate.hql.ast.QueryTranslatorImpl.analyze（QueryTranslatorImpl.java:189）在org.hibernate.hql.ast.QueryTranslatorImpl.doCompile（QueryTranslatorImpl.java:130）在org.hibernate.hql.ast.QueryTranslatorImpl.compile（QueryTranslatorImpl.java:83）在org.hibernate.impl.SessionFactoryImpl.getQuery（SessionFactoryImpl.java:425）在org.hibernate.impl.SessionImpl.getQueries（SessionImpl.java:880）在org.hibernate.impl.SessionImpl.executeUpdate（SessionImpl.java:861）在org.hibernate.impl.QueryImpl.executeUpdate（QueryImpl.java:89）在com.njob.dao.AccountDao.passlink（AccountDao.java:213）在com.njob.action.companylink.doPost（companylink.java:34）在javax.servlet.http.HttpServlet.service（HttpServlet.java:709）在javax.servlet.http.HttpServlet.service（HttpServlet.java:802）在org.apache.catalina.core.ApplicationFilterChain.internalDoFilter（ApplicationFilterChain.java:237）在org.apache.catalina.core.ApplicationFilterChain.doFilter（ApplicationFilterChain.java:157）在org.apache.catalina.core.StandardWrapperValve.invoke（StandardWrapperValve.java:214）在org.apache.catalina.core.StandardContextValve.invoke（StandardContextValve.java:178）在org.apache.catalina.core.StandardHostValve.invoke（StandardHostValve.java:126）在org.apache.catalina.valves.ErrorReportValve.invoke（ErrorReportValve.java:105）在org.apache.catalina.core.StandardEngineValve.invoke（StandardEngineValve.java:107）在org.apache.catalina.connector.CoyoteAdapter.service（CoyoteAdapter.java:148）在org.apache.coyote.http11.Http11Processor.process（Http11Processor.java:825）在org.apache.coyote.http11.Http11Protocol $ Http11ConnectionHandler.processConnection（Http11Protocol.java:731）在org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket（PoolTcpEndpoint.java:526）在org.apache.tomcat.util.net.LeaderFollowerWorkerThread.runIt(LeaderFollowerWorkerThread.java:80） at org.apache.tomcat.util.threads.ThreadPool $ ControlRunnable.run（ThreadPool.java:684）在java.lang.Thread.run（未知来源）

Answer 1

将查询更改为

String queryString="UPDATE account SET companyname = :companyName WHERE companyname like 'm' AND email LIKE :mailName";

并使用

query.setParameter("companyName", companyName);
query.setParameter("mailName", mailName);

查看

Native SQL query with hibernate

Answer 2

试试这个

 query.setParameter("companyName", companyName);

您使用的参数是companyName

如何在hibernate中用条件写更新查询

2 个答案: