我的页面有一个菜单,这里是Onmouseover,Onmouseout img
<img id='wits' class="wits1" src="Images/MenuInWhite/ContactButton1.png" onmouseover="this.src='Images/mouseover/ContactButton2.png'"
onmouseout="this.src='Images/MenuInWhite/ContactButton1.png'" /><br />
<img id='city' class="city1" src="Images/MenuInWhite/ActivitiesButton1.png" onmouseover="this.src='Images/mouseover/ActivitiesButton2.png'"
onmouseout="this.src='Images/MenuInWhite/ActivitiesButton1.png'" /><br />
<img id='organise' class="city1" onmouseout="this.src='Images/MenuInWhite/CruisesButton1.png';"
onmouseover="this.src='Images/mouseover/CruisesButton2.png';" src="Images/MenuInWhite/CruisesButton1.png" /><br />
<img id='people' class="city1" onmouseout="this.src='Images/MenuInWhite/HomeButton1.png';"
onmouseover="this.src='Images/mouseover/HomeButton2.png';" src="Images/MenuInWhite/HomeButton1.png" /><br />
每当我将鼠标放在图像上时,图像必须改变,当我将鼠标移开时,必须将其更改为原始图片,它工作正常,
我想知道每当我选择任何图像时该怎么做,该图像必须更改为在图像上移动鼠标时显示的图像。当我选择任何其他图像时,必须进行相同的处理,但必须将之前更改的图像更改回原始图像。
请帮我解决这个问题,
提前致谢
答案 0 :(得分:2)
这是一个纯粹的JavaScript解决方案,可能会有所帮助
function isMSIE()
{
var ie7 =
(document.all && !window.opera && window.XMLHttpRequest) ? true : false;
return ie7;
}
function getParent(element, depth)
{
var rVal = element;
if (isMSIE()) {
for (i = 0; i < depth; i++)
rVal = rVal.parentElement;
}
else {
for (i = 0; i < depth; i++)
rVal = rVal.parentNode;
}
return rVal;
}
function clicked(sender)
{
var parent = getParent(sender, 1);
var imgs = parent.getElementsByTagName("IMG");
for(i=0; i<imgs.length; i++)
{
if (imgs[i] != sender) {
imgs[i].src = 'Images/MenuInWhite/ContactButton1.png';
imgs[i].onmouseout =
function () { this.src = 'Images/MenuInWhite/HomeButton1.png'; };
}
else {
imgs[i].src = 'Images/MenuInWhite/HomeButton1.png';
imgs[i].onmouseout = null;
}
if(imgs[i]!=sender)
imgs[i].src = 'Images/MenuInWhite/HomeButton1.png';
}
}
<div>
<img id='wits' class="wits1"
src="Images/MenuInWhite/ContactButton1.png"
onmouseover="this.src='Images/mouseover/ContactButton2.png'"
onmouseout="this.src='Images/MenuInWhite/ContactButton1.png'"
onclick="clicked(this);" /><br />
// Just add this onclick="clicked(this);" on each img
</div>