我正在尝试在Windows上录制音频,这是我的代码。它适用于8位,但它不能用于16位。谁能帮我? #包括 #包括 #包括 #pragma comment(lib,“winmm.lib”) 使用namespace std;
int test(){
HWAVEIN microHandle;
WAVEHDR waveHeader;
MMRESULT result = 0;
WAVEFORMATEX waveformat;
waveformat.wFormatTag = WAVE_FORMAT_PCM;
waveformat.wBitsPerSample=8;
waveformat.nSamplesPerSec=16000;//8000;
waveformat.nAvgBytesPerSec=waveformat.nSamplesPerSec*waveformat.nSamplesPerSec/8;
waveformat.nChannels=1;
waveformat.nBlockAlign=waveformat.nChannels*waveformat.wBitsPerSample/8;
waveformat.cbSize=0;
result = waveInOpen(µHandle, WAVE_MAPPER, &waveformat, 0L, 0L, CALLBACK_EVENT);
if (result)
{
cout << "Fail step 1" << endl;
cout << result << endl;
Sleep(10000);
return 0;
}
const int BUFSIZE = 16000*4;
char * buf = (char *)malloc(BUFSIZE);
// Set up and prepare header for input
waveHeader.lpData = (LPSTR)buf;
waveHeader.dwBufferLength = BUFSIZE;
waveHeader.dwBytesRecorded=0;
waveHeader.dwUser = 0L;
waveHeader.dwFlags = 0L;
waveHeader.dwLoops = 0L;
waveInPrepareHeader(microHandle, &waveHeader, sizeof(WAVEHDR));
// Insert a wave input buffer
result = waveInAddBuffer(microHandle, &waveHeader, sizeof(WAVEHDR));
if (result)
{
cout << "Fail step 2" << endl;
cout << result << endl;
Sleep(10000);
return 0;
}
result = waveInStart(microHandle);
if (result)
{
cout << "Fail step 3" << endl;
cout << result << endl;
Sleep(10000);
return 0;
}
// Wait until finished recording
do {} while (waveInUnprepareHeader(microHandle, &waveHeader, sizeof(WAVEHDR))==WAVERR_STILLPLAYING);
FILE *fp = fopen("output.pcm","w");
fwrite(buf,1,BUFSIZE,fp);
fclose(fp);
waveInClose(microHandle);
return 0;
}
void main()
{
test();
}
如果我设置参数waveformat.wBitsPerSample = 8,它可以正确录制音频, 但如果我将它设置为waveformat.wBitsPerSample = 16,它会记录噪音!!! 任何人都可以帮助我吗?
感谢。
答案 0 :(得分:0)
它应该是FILE * fp = fopen(“output.pcm”,“wb”); NOT FILE * fp = fopen(“output.pcm”,“w”);