我在下面的代码会在您更改国家/地区列表时更改状态下拉列表 如果选择国家ID号234和224,如何更改状态列表? 如果选择了其他国家/地区,则应将其更改为此文本输入框
<input type="text" name="othstate" value="" class="textBox">
表格
<form method="post" name="form1">
<select style="background-color: #ffffa0" name="country" onchange="getState(this.value)">
<option>Select Country</option>
<option value="223">USA</option>
<option value="224">Canada</option>
<option value="225">England</option>
<option value="226">Ireland</option>
</select>
<select style="background-color: #ffffa0" name="state">
<option>Select Country First</option>
</select>
javascript
<script>
function getState(countryId)
{
var strURL="findState.php?country="+countryId;
var req = getXMLHTTP();
if (req)
{
req.onreadystatechange = function()
{
if (req.readyState == 4)
{
// only if "OK"
if (req.status == 200)
{
document.getElementById('statediv').innerHTML=req.responseText;
} else {
alert("There was a problem while using XMLHTTP:\n" + req.statusText);
}
}
}
req.open("GET", strURL, true);
req.send(null);
}
}
</script>
答案 0 :(得分:5)
只需在执行AJAX请求之前检查countryId值,并仅在countryId处于允许范围内时执行请求。在countryId不匹配的情况下,我会隐藏选择(也可能清除它的值)并显示之前隐藏的已存在的输入。如果选择了允许的国家,则应该采取相反的措施。
下面的jQuery示例:
<form method="post" name="form1">
<select style="background-color: #ffffa0" name="country" onchange="getState(this.value)">
<option>Select Country</option>
<option value="223">USA</option>
<option value="224">Canada</option>
<option value="225">England</option>
<option value="226">Ireland</option>
</select>
<select style="background-color: #ffffa0" name="state">
<option>Select Country First</option>
</select>
<input type="text" name="othstate" value="" class="textBox" style="display: none;">
</form>
$(function() {
$('#country').change( function() {
var val = $(this).val();
if (val == 223 || val == 224) {
$('#othstate').val('').hide();
$.ajax({
url: 'findState.php',
dataType: 'html',
data: { country : val },
success: function(data) {
$('#state').html( data );
}
});
}
else {
$('#state').val('').hide();
$('#othstate').show();
}
});
});
答案 1 :(得分:1)
我认为简单的做法是提供一个状态下拉列表和一个包含不同ID的文本输入框。将两者的显示设置为无,然后您只需要用
包围getState()的内容if (countryId == 233 || countryId == 234) {
/* Ajax state population here */
dropdownId.display = 'block';
textEntryId.display = 'none';
}
else {
textEntryId.display = 'block';
dropdownId.display = 'none';
}
(其中dropdownId
和textEntryId
是相关UI组件的ID),因此您可以在选择时启用/显示状态下拉列表或文本条目的显示。
JQuery一切都很好,但我不会介绍只是来解决这个问题。
答案 2 :(得分:1)
编辑:这是一个非常适合任务的解决方案,适应了Tvanfosson的界限:
<script type="text/javascript" src="http://code.jquery.com/jquery-latest.min.js">
</script>
<script>
$(function() {
$('#country').change( function() {
var val = $(this).val();
if (val == 223 || val == 224) {
$('#othstate').val('').hide();
$.ajax({
url: 'findState.php',
dataType: 'html',
data: { country : val },
success: function(data) {
$('#state').html( data );
}
});
}
else {
$('#state').val('').hide();
$('#othstate').show();
}
});
});
</script>
<select style="background-color: #ffffa0" name="country" id=country >
<option>Select Country</option>
<option value="223">USA</option>
<option value="224">Canada</option>
<option value="225">England</option>
<option value="226">Ireland</option>
</select>
<select style="background-color: #ffffa0" name="state">
<option>Select Country First</option>
</select>
<input type="text" name="othstate" id=othstate value="" class="textBox" style="display: none;">
正如您所看到的,我删除了<form>
元素,这不是绝对必要但可以添加(如果在用户端停用JS,则必须正确使用。)
here
我还删除了被'change()`jquery函数替换的onchange
事件。
答案 3 :(得分:0)
VK API只需选择国家/地区,获取ID并从
中选择城市
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.0/jquery.min.js"></script>
<script src="http://code.jquery.com/jquery-latest.js"></script>
<script type="text/javascript">
var $j = jQuery.noConflict();
var _getCountry = function() {
$j.ajax({
url: "http://api.vk.com/method/database.getCountries",
data: {
'v': 5.5,
'need_all': 0,
'code' : 'RU,UA,BY,KZ,KG,LV,EE'
// 'count': 10
},
dataType: 'jsonp',
success: function(data, status) {
if (status !== 'success') {
return false;
}
console.log(data.response, status);
$j.each(data.response.items, function(i, item) {
console.log("each country");
var newOption = '<option id="' + item.id + '" value="' + item.title + '">' + item.title + '</option>';
country_options.push(newOption);
});
document.getElementById('countrylist').innerHTML = country_options;
}
});
}
var _getCity = function(country_id) {
$j.ajax({
url: "http://api.vk.com/method/database.getCities",
data: {
'v': 5.61,
'need_all': 0,
'country_id': country_id
},
dataType: 'jsonp',
success: function(data, status) {
if (status !== 'success') {
return false;
}
console.log(data.response, status);
$j.each(data.response.items, function(i, item) {
console.log("each city");
var newOption = '<option id="' + item.id + '" value="' + item.title + '">' + item.title + '</option>';
city_options.push(newOption);
});
document.getElementById('citylist').innerHTML = city_options;
}
});
}
var city_options = [];
var country_options = [];
$j(document).ready(function () {
_getCountry();
$j('#country').on('input',function() {
var opt = $j('option[value="'+$j(this).val()+'"]');
var countryid = opt.attr('id');
_getCity(countryid);
});
});
</script>
&#13;
<div class="form-group">
<label class="col-lg-4 control-label">Страна:</label>
<div class="col-lg-8">
<div class="controls">
<input name="country" list="countrylist" id="country" class="form-control" />
<datalist id="countrylist">
</datalist>
</div>
</div>
</div>
<div class="form-group">
<label class="col-lg-4 control-label">Город:</label>
<div class="col-lg-8">
<input name="city" list="citylist" id="city" class="form-control"/>
<datalist id="citylist">
</datalist>
</div>
</div>
&#13;
答案 4 :(得分:0)
////////////////// connection file con.php rishabh
<?php
ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$conn = mysql_connect($dbhost, $dbuser, $dbpass);
if(! $conn ) {
die('Could not connect: ' . mysql_error());
}
mysql_select_db( 'testajax' );
?>
/////////////////////////// index.php rishabh
<script src="https://code.jquery.com/jquery-1.12.4.min.js"></script>
<?php
include('con.php');
?>
<form>
<div class="frmDronpDown">
<div class="row">
<table><tr><td><label>Country:</label><br/>
<select name="country" id="country" data-name="country" class="demoInputBox" onChange="getCountry(this.value);">
<option value="">Select Country</option>
<?php
$sql = mysql_query("SELECT distinct country FROM statecont ");
while($result=mysql_fetch_array($sql)){
?>
<option value="<?php echo $result['country']; ?>"><?php echo $result['country']; ?></option>
<?php
}
?>
</select> </td>
<td>
<label>Phone:</label><br/>
<select name="phone" id="phone" data-name="phone" class="demoInputBox" onChange="getPhone(this.value);">
<option value="">Select Country</option>
<?php
$sql = mysql_query("SELECT distinct phone FROM statecont ");
while($result=mysql_fetch_array($sql)){
?>
<option value="<?php echo $result['phone']; ?>"><?php echo $result['phone']; ?></option>
<?php
}
?>
</select>
</td></tr></table>
</div>
<div id="state-list"></div>
</div>
</form>
<script>
function getCountry(val) {
var dataname = $('#country').attr('data-name');
console.log(dataname);
$.ajax({
type: "POST",
url: "data.php",
data: {
value_name: val,
colomn_name: dataname
},
success: function (data){
$("#state-list").html(data);
}
});
}
function getPhone(val) {
var dataname = $('#phone').attr('data-name');
console.log(dataname);
$.ajax({
type: "POST",
url: "data.php",
data: {
value_name: val,
colomn_name: dataname
},
success: function (data){
$("#state-list").html(data);
}
});
}
</script>
// ////////////////////data file data.php rishabh
<?php
$val = $_POST["value_name"];
$colomn = $_POST["colomn_name"];
include('con.php');
$sql_aa = mysql_query("SELECT * FROM statecont where ".$colomn."='$val'"); ?>
<table>
<tr><td>State</td><td>Countery</td></tr>
<?php while($result_aa=mysql_fetch_array($sql_aa)){ ?>
<tr><td><?php echo $result_aa['state']; ?></td><td><?php echo $result_aa['country']; ?></td></tr>
<?php } ?>
</table>
答案 5 :(得分:0)
**index.html**
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Populate City Dropdown Using jQuery Ajax</title>
<script src="https://code.jquery.com/jquery-1.12.4.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$("select.country").change(function(){
var selectedCountry = $(".country option:selected").val();
$.ajax({
type: "POST",
url: "ajaxServer.jsp",
data: { country : selectedCountry }
}).done(function(data){
$("#response").html(data);
});
});
});
</script>
<style>
select { width: 10em }
</style>
</head>
<body>
<form>
<table>
<tr>
<td> <label>Country:</label></td>
<td> <select class="country">
<option>Select</option>
<option value="usa">United States</option>
<option value="india">India</option>
<option value="uk">United Kingdom</option>
</select>
</td>
</tr>
<tr><td >
<label>States:</label></td>
<td> <select id="response">
<option>Select State</option>
</select>
</td></tr>
</table>
</form>
</body>
</html>
**ajaxServer.jsp**
<option>Select State</option>
<%
String count=request.getParameter("country");
String india[]={"Mumbai", "New Delhi", "Bangalore"};
String usa[]={"New Yourk", "Los Angeles","California"};
String uk[]={"London", "Manchester", "Liverpool"};
String states[];
if(count.equals("india"))
{
for(int i=0;i<=2;i++)
{
out.print("<option>"+india[i]+"</option>");
}
}
else if(count.equals("usa"))
{
for(int i=0;i<usa.length;i++)
{
out.print("<option>"+usa[i]+"</option>");
}
}
else if(count.equals("uk"))
{
for(int i=0;i<=2;i++)
{
out.print("<option>"+uk[i]+"</option>");
}
}
%>