我有两张桌子:
teams
----------------
|uid|name |rank|
----------------
| 1 |Team1| 1 |
| 2 |Team2| 2 |
----------------
games
-----------------------------------------------------------------------
|uid|team_one_uid|team_one_score|team_two_uid|team_two_score|game_date|
-----------------------------------------------------------------------
|1|1|70|2|50|2012-12-12|
团队表有一个团队列表和其他数据,如排名。 游戏表有一个游戏列表,并通过它的唯一ID(uid)引用每个团队。 我可以运行什么查询以查看包含具有以下列的行的结果:
game_uid, team_one_name, team_one_rank, team_one_score, team_two_name, team_two_rank, team_two_score, game_date
答案 0 :(得分:11)
select g.uid as game_uid,
t1.name as team_one_name,
t1.rank as team_one_rank,
team_one_score,
t2.name as team_two_name,
t2.rank as team_two_rank,
team_two_score,
game_date
from games g
inner join teams t1 on t1.uid = team_one_uid
inner join teams t2 on t2.uid = team_two_uid
答案 1 :(得分:1)
我认为这就是你要找的东西:
SELECT g.uid AS game_uid, t1.name AS team_one_name, t1.rank AS team_one_rank,
g.team_one_score, t2.name AS team_two_name, t2.rank AS team_two_rank,
g.team_two_score, g.game_date
FROM `games` g, `teams` t1, `teams` t2
WHERE t1.id = g.team_one_uid
AND t2.id = g.team_two_uid
这也可以通过INNER JOIN
完成,但它也可以达到相同的目的。