我公司的部署过程要求用于创建过程和表等的SQL脚本是裸露的。
在SQL Server Management Studio中生成创建脚本不仅仅是一个裸脚本,在这种情况下很不幸。例如,对于测试表,这就是SSMS为我生成的内容:
USE [DemoDB]
GO
/****** Object: Table [dbo].[example] Script Date: 08/07/2012 15:46:32 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE TABLE [dbo].[example](
[fake_row] [int] NULL
) ON [PRIMARY]
GO
所以,我想知道的是:
我可以以某种方式在SSMS中运行SQL Server上的查询,它会给我一个字面上只有以下内容的脚本吗?
create table example (
fake_row int
)
答案 0 :(得分:4)
您可以使用information_schema(Aaron ...我知道,INFORMATION_SCHEMA;)创建您自己的“创建表”语句。
我为此目的编写了一些代码,但它没有使用INFORMATION_SCHEMA。我知道,如果使用可能计划删除的旧系统表。它还添加了一些额外的信息(您可以删除,因为您不需要它)。只需将表列表放在@INclusiveLIST中,然后在表所在的数据库中运行它。
SET @INCLUSIONLIST = '|table1|table2|';
SELECT (CASE WHEN rownum = 1 THEN 'CREATE TABLE ['+a.t_name+'] ('
WHEN c.column_id IS NOT NULL
THEN ' ['+c.c_name+'] ' +
(CASE WHEN CHARINDEX('CHAR', datatype) > 0 THEN datatype+'('+(case when length < 0 then 'max' else cast(length as varchar) end)+')'
WHEN CHARINDEX('BINARY', datatype) > 0 THEN datatype+'('+cast(length as varchar)+')'
WHEN datatype = 'float' AND precision <> 24 THEN datatype+'('+cast(precision as varchar)+')'
WHEN datatype IN ('numeric', 'decimal') AND scale = 0 THEN datatype+'('+cast(precision as varchar)+')'
WHEN datatype IN ('numeric', 'decimal') AND scale > 0 THEN datatype+'('+cast(precision as varchar)+','+cast(scale as varchar)+')'
ELSE datatype END)+' '+
(CASE WHEN c.identity_seed IS NOT NULL
THEN 'IDENTITY(' + CAST(identity_seed AS VARCHAR) + ',' + CAST(identity_increment AS VARCHAR) + ') '
ELSE '' END) +
(CASE WHEN c.is_nullable = 0 THEN 'NOT NULL ' ELSE '' END) +
(CASE WHEN c.default_definition IS NOT NULL
THEN 'DEFAULT '+default_definition ELSE '' END) +
(CASE WHEN max_column_id = column_id AND pk.pk_name IS NULL THEN '' ELSE ',' END)
WHEN rownum = max_column_id + 2 and pk.pk_name IS NOT NULL
THEN ' PRIMARY KEY ('+pk.pk_columns+')'
WHEN rownum = max_column_id + 3 THEN ') /* CREATE TABLE '+a.t_name+' */'
WHEN rownum = max_column_id + 4 THEN 'GO'
WHEN rownum = max_column_id + 5 THEN ''
END)
FROM (SELECT t.t_name, rownum, max_column_id
FROM (SELECT t.name as t_name, MAX(c.column_id) as max_column_id
FROM sys.columns c join
(SELECT * FROM sys.tables WHERE CHARINDEX('|'+name+'|', @INCLUSIONLIST) > 0 ) t
ON c.object_id = t.object_id
GROUP BY t.name) t join
(SELECT ROW_NUMBER() OVER (ORDER BY object_id) as rownum FROM sys.columns c) ctr
ON ctr.rownum <= t.max_column_id + 5
) a LEFT OUTER JOIN
(SELECT t.name as t_name, c.column_id, c.name AS c_name, u.name as datatype,
ISNULL(baset.name, N'') AS systemtype,
CAST(CASE WHEN baset.name IN (N'nchar', N'nvarchar') AND c.max_length <> -1
THEN c.max_length/2 ELSE c.max_length END AS INT) AS length,
c.precision AS precision,
c.scale as scale,
c.is_nullable,
dc.definition as default_definition,
idc.seed_value as identity_seed, idc.increment_value as identity_increment
FROM sys.tables t JOIN
sys.all_columns AS c
ON c.object_id = t.object_id LEFT OUTER JOIN
sys.types u
ON u.user_type_id = c.user_type_id LEFT OUTER JOIN
sys.types baset
ON baset.user_type_id = c.system_type_id AND
baset.user_type_id = baset.system_type_id LEFT OUTER JOIN
sys.default_constraints dc
ON c.object_id = dc.parent_object_id AND
c.column_id = dc.parent_column_id LEFT OUTER JOIN
sys.identity_columns idc
ON c.object_id = idc.object_id AND
c.column_id = idc.column_id
) c
ON a.t_name = c.t_name AND
c.column_id + 1 = a.rownum LEFT OUTER JOIN
(SELECT t.name as t_name, kc.name as pk_name,
(MAX(CASE WHEN index_column_id = 1 THEN '['+c.name+']' ELSE '' END) +
MAX(CASE WHEN index_column_id = 2 THEN ','+'['+c.name+']' ELSE '' END) +
MAX(CASE WHEN index_column_id = 3 THEN ','+'['+c.name+']' ELSE '' END) +
MAX(CASE WHEN index_column_id = 4 THEN ','+'['+c.name+']' ELSE '' END) +
MAX(CASE WHEN index_column_id = 5 THEN ','+'['+c.name+']' ELSE '' END) +
MAX(CASE WHEN index_column_id = 6 THEN ','+'['+c.name+']' ELSE '' END) +
MAX(CASE WHEN index_column_id = 7 THEN ','+'['+c.name+']' ELSE '' END) +
MAX(CASE WHEN index_column_id = 8 THEN ','+'['+c.name+']' ELSE '' END) +
MAX(CASE WHEN index_column_id = 9 THEN ','+'['+c.name+']' ELSE '' END) +
MAX(CASE WHEN index_column_id = 10 THEN ','+'['+c.name+']' ELSE '' END)
) as pk_columns
FROM sys.indexes i JOIN
sys.key_constraints kc
ON i.name = kc.name AND
kc.type = 'PK' JOIN
sys.tables t
ON i.object_id = t.object_id JOIN
sys.index_columns ic
ON i.object_id = ic.object_id AND
i.index_id = ic.index_id JOIN
sys.columns c
ON ic.index_column_id = c.column_id AND
ic.object_id = c.object_id
GROUP BY t.name, kc.name
) pk
ON pk.t_name = a.t_name
ORDER BY a.t_name, rownum
答案 1 :(得分:3)
为自我答案道歉,标记其他好的答案+1。
事实证明,你可以在SSMS中使用实用工具。
答案 2 :(得分:2)
您可以选择控制SSMS的常规脚本行为,如:Options for scripting SQL Server database objects。
答案 3 :(得分:1)
我会创建从INFORMATION_SCHEMA视图中读取的存储过程。 获取存储过程文本只是:
DECLARE @SQL VARCHAR(8000)
SET @SQL=' '
select @SQL = @SQL + ROUTINE_DEFINITION
from INFORMATION_SCHEMA.ROUTINES
where ROUTINE_TYPE='PROCEDURE'
AND SPECIFIC_NAME = 'updateComments'
PRINT @SQL
脚本表的那个看起来像:
DECLARE @tableName VARCHAR(50)
SET @tableName = 'Location'
-- Need to know how many columns
DECLARE @NumColumns int
SELECT @NumColumns = MAX(ORDINAL_POSITION)
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = @tableName
DECLARE @SQL VARCHAR(8000)
SET @SQL=' '
DECLARE @Results TABLE
(LineNumber int,
Line VARCHAR(1000))
INSERT INTO @Results
SELECT 0 AS ORDINAL_POSITION,
'CREATE TABLE '+TABLE_SCHEMA+'.'+@tableName+' (' AS Line
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_NAME = @tableName
UNION ALL
SELECT ORDINAL_POSITION,
'['+COLUMN_NAME+'] '+ DATA_TYPE +
CASE WHEN DATA_TYPE = 'varchar' OR DATA_TYPE = 'char'
THEN '('+ CAST(CHARACTER_MAXIMUM_LENGTH AS VARCHAR) +')'
ELSE '' END +
CASE WHEN IS_NULLABLE = 'NO'
THEN ' NULL '
ELSE ' NOT NULL' END +
CASE WHEN ORDINAL_POSITION < @NumColumns
THEN ', '
ELSE ' ' END
AS LINE
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = @tableName
UNION ALL
SELECT 999, ' )'
SELECT Line
FROM @Results
ORDER BY LineNumber
SELECT @SQL = @SQL + Line
FROM @Results
ORDER BY LineNumber
SELECT @SQL
PRINT @SQL
这会创建您想要的简单表脚本,但它不完整 - 不执行数字精度,主键等。但这足以让您入门。
我只是将其中的每一个都变成一个以对象名作为参数的存储过程。